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我为 Reporting Services 2005 开发了自己的交付扩展，以将其与我们的 SaaS 营销解决方案集成。

它接受订阅，并使用一组自定义参数拍摄报告的快照。然后它呈现报告，发送带有链接的电子邮件，并将报告附加为 XLS。

一切正常，直到邮件交付......

这是我发送电子邮件的代码：

 public static List<string> SendMail(SubscriptionData data, Stream reportStream, string reportName, string smptServerHostname, int smtpServerPort)
{
  List<string> failedRecipients = new List<string>();

  MailMessage emailMessage = new MailMessage(data.ReplyTo, data.To);
  emailMessage.Priority = data.Priority;
  emailMessage.Subject = data.Subject;
  emailMessage.IsBodyHtml = false;
  emailMessage.Body = data.Comment;

  if (reportStream != null)
  {
    Attachment reportAttachment = new Attachment(reportStream, reportName);
    emailMessage.Attachments.Add(reportAttachment);
    reportStream.Dispose();
  }

  try
  {
    SmtpClient smtp = new SmtpClient(smptServerHostname, smtpServerPort);

    // Send the MailMessage
    smtp.Send(emailMessage);
  }
  catch (SmtpFailedRecipientsException ex)
  {
    // Delivery failed for the recipient. Add the e-mail address to the failedRecipients List
    failedRecipients.Add(ex.FailedRecipient);
  }
  catch (SmtpFailedRecipientException ex)
  {
    // Delivery failed for the recipient. Add the e-mail address to the failedRecipients List
    failedRecipients.Add(ex.FailedRecipient);
  }
  catch (SmtpException ex)
  {
    throw ex;
  }
  catch (Exception ex)
  {
    throw ex;
  }

  // Return the List of failed recipient e-mail addresses, so the client can maintain its list.
  return failedRecipients;
}

SmtpServerHostname 的值为 localhost，端口为 25。

我非常确信我可以使用 Telnet 发送邮件。它有效。

这是我从 SSRS 收到的错误消息：

ReportingServicesService!notification!4!08/28/2008-11:26:17:: 通知 6ab32b8d-296e-47a2-8d96-09e81222985c 已完成。成功：False，状态：异常消息：发送邮件失败。Stacktrace：在 C:\inetpub\wwwroot\CustomReporting\MyDeliveryExtension\MailDelivery.cs 中的 MyDeliveryExtension.MailDelivery.SendMail(SubscriptionData data, Stream reportStream, String reportName, String smptServerHostname, Int32 smtpServerPort)：第 48 行在 MyDeliveryExtension.MyDelivery.Deliver(Notification通知）在 C:\inetpub\wwwroot\CustomReporting\MyDeliveryExtension\MyDelivery.cs:line 153，DeliveryExtension：我的交付，报告：点击开发，尝试 1 ReportingServicesService！dbpolling！4！08/28/2008-11:26:17 :: NotificationPolling完成处理项6ab32b8d-296e-47a2-8d96-09e81222985c

这可能与信任/代码访问安全有关吗？

我的交付扩展在 rssrvpolicy.config 中获得了完全信任：

   <CodeGroup 
    class="UnionCodeGroup"
    version="1"
    PermissionSetName="FullTrust"
    Name="MyDelivery_CodeGroup"
    Description="Code group for MyDelivery extension">
    <IMembershipCondition class="UrlMembershipCondition" version="1" Url="C:\Program Files\Microsoft SQL Server\MSSQL.2\Reporting Services\ReportServer\bin\MyDeliveryExtension.dll" />
   </CodeGroup>

信任在这里会是一个问题吗？

另一种理论：SQL Server 和 SSRS 安装在本地系统的安全上下文中。我是对的，还是此服务帐户限制了对任何网络资源的访问？甚至它自己的 SMTP 服务器？

我尝试将所有 SQL Server 服务登录更改为管理员 - 但仍然没有任何成功。

我还尝试在我的代码中登录 SMTP 服务器，方法是提供： NetworkCredential("Administrator", "password") 和 NetworkCredential("Administrator", "password", "MyRepServer")

有人可以在这里帮忙吗？

4

5 回答 5

0

在什么地方：

at MyDeliveryExtension.MailDelivery.SendMail(SubscriptionData data, Stream reportStream, String reportName, String smptServerHostname, Int32 smtpServerPort) 
  in C:\inetpub\wwwroot\CustomReporting\MyDeliveryExtension\MailDelivery.cs:line 48 

at MyDeliveryExtension.MyDelivery.Deliver(Notification notification) 
  in C:\inetpub\wwwroot\CustomReporting\MyDeliveryExtension\MyDelivery.cs:line 153

此外，您似乎正在处理报告流，但这应该通过打开该流的任何方式来完成，而不是您的方法（附加流会处理它并不明显）。

由于重新抛出异常的方式，您正在丢失部分堆栈跟踪。不要抛出 ex 变量，只要 throw 就足够了。

试试这个调整：

public static List<string> SendMail(SubscriptionData data, Stream reportStream, string reportName, string smptServerHostname, int smtpServerPort)
{
  List<string> failedRecipients = new List<string>();

  MailMessage emailMessage = new MailMessage(data.ReplyTo, data.To) {
      Priority = data.Priority,
      Subject = data.Subject,
      IsBodyHtml = false,
      Body = data.Comment
  };

  if (reportStream != null)
    emailMessage.Attachments.Add(new Attachment(reportStream, reportName));

  try
  {
      SmtpClient smtp = new SmtpClient(smptServerHostname, smtpServerPort);

      // Send the MailMessage
      smtp.Send(emailMessage);
  }
  catch (SmtpFailedRecipientsException ex)
  {
    // Delivery failed for the recipient. Add the e-mail address to the failedRecipients List
    failedRecipients.Add(ex.FailedRecipient);

    //are you missing a loop here? only one failed address will ever be returned
  }
  catch (SmtpFailedRecipientException ex)
  {
    // Delivery failed for the recipient. Add the e-mail address to the failedRecipients List
    failedRecipients.Add(ex.FailedRecipient);
  }

  // Return the List of failed recipient e-mail addresses, so the client can maintain its list.
  return failedRecipients;
}
于 2008-08-28T11:57:23.917 回答
0

我试图删除 reportStream 附件：

  //if (reportStream != null)    
     //emailMessage.Attachments.Add(new Attachment(reportStream, reportName));

现在它工作正常。

所以这与reportStream有关。

于 2008-08-28T13:33:52.047 回答
0

在玩弄了获取reportStream的功能之后，我能够解决邮件发送问题。

错误不在 SendMail 方法中，而是在其他地方。异常是在 SendMail 的上下文中引发的。搞砸了！

于 2008-08-28T14:33:50.187 回答
0

这就是为什么你必须避免：

catch (Exception ex)
{
    throw ex;
}

因为这基本上将您的异常隐藏在一个新的异常中。

如果您使用：

catch (Exception ex)
{
    throw; //note: no ex
}

它保留原始异常和堆栈跟踪。

于 2008-08-29T16:43:14.227 回答
0 
FileStream m_fileStream = null;

m_files = notification.Report.Render(format, null);
RenderedOutputFile m_renderedOutputFile = m_files[0];
m_fileStream = new FileStream(fileName, FileMode.Create, FileAccess.Write);
m_renderedOutputFile.Data.Seek((long)0, SeekOrigin.Begin);
byte[] arr = new byte[(int)m_renderedOutputFile.Data.Length + 1];

m_renderedOutputFile.Data.Read(arr, 0, (int)m_renderedOutputFile.Data.Length);

m_fileStream.Write(arr, 0, (int)m_renderedOutputFile.Data.Length);

m_fileStream.Close();
于 2010-01-14T16:31:47.960 回答