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我编写的另一个串行代码运行良好，但是这个并行版本没有给出任何输出，它只是打印你好，我正在用“嘿”测试它，它甚至从未到达那一行，即它卡在调用方法上，我不能在网上找不到任何有用的资源。

请帮助我了解我哪里出错了我是并行编程的新手。

该代码是一个中值滤波程序，当给定一个数组 x=[2,80,6,3] 时，过滤后的数组是 y=[2,6,6,3]，计算如下：

y[1] = 中位数[2 2 80] = 2

y[2] = 中值[2 80 6] = 中值[2 6 80] = 6

y[3] = 中值[80 6 3] = 中值[3 6 80] = 6

y[4] = 中值[6 3 3] = 中值[3 3 6] = 3

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
import java.util.concurrent.ForkJoinPool;
import java.util.concurrent.RecursiveAction;
import java.io.PrintWriter;

public class ParallelFilter extends RecursiveAction {

static final int SEQUENTIAL_THRESHOLD=500; 
ArrayList<Float> inputArray;
int sizeOfFilter;
ArrayList<Float> outputlist;
ArrayList<Float> arrayFiltered;

float high;
float low;

public ParallelFilter(ArrayList<Float> inputArray,int sizeOfFilter,float           high,float low)
                 {
  
  this.inputArray=inputArray;
   this.outputlist=outputlist;
  this.sizeOfFilter=sizeOfFilter;
  this.arrayFiltered=arrayFiltered;
  //this.index=index;
  this.high=high;
  this.low=low;
 }




 protected void compute()
 {
  int index=1;
  
  if((high - low) < SEQUENTIAL_THRESHOLD )
  {
      while(inputArray.size() > sizeOfFilter){
     for(int i=0; i<sizeOfFilter;i++){
        
         arrayFiltered.add(i,inputArray.get(i));
         
     }
     
         Collections.sort(arrayFiltered);
         float median = arrayFiltered.get(arrayFiltered.size()/2);
         outputlist.add(index,median);
         inputArray.remove(inputArray.get(0));
         arrayFiltered.clear();
         index=index+1;
      
      }
      
      outputlist.add(inputArray.get(inputArray.size()-1));
  }
  
  
    else{
      
      ParallelFilter leftTask = new       ParallelFilter(inputArray,sizeOfFilter,low,(low+high)/2);
      ParallelFilter rightTask = new ParallelFilter(inputArray,sizeOfFilter,(low+high)/2,high);
      leftTask.fork();
      rightTask.compute();
      leftTask.join();
  }
  
  }



   public static void main(String[] args){
  
  try
  {
      Scanner sc;
      sc = new Scanner(new File("inp1.txt"));
      sc.useDelimiter(" ");
      ArrayList<Float> inputlist = new ArrayList<>();
      
      //POPULATE LIST FROM FILE
      while (sc.hasNextLine()) {
          
      if(sc.nextLine().length() == 1){continue;}
      String[] parts = sc.nextLine().split(" "); // split each line by " "
 
      inputlist.add(Float.parseFloat(parts[1]))  ; 
      // System.out.println(parts[1]);
                           }
    
      System.out.println("Enter filter size : ");
      Scanner in = new Scanner(System.in);
      int sizeOfFilter = in.nextInt();
      if (sizeOfFilter < 3 || sizeOfFilter / 2 == 0) {
             System.out.println("Filter size should be odd and bigger than 3");
         }
      
      float low = inputlist.get(0);
      float high = inputlist.get(inputlist.size()-1);
      
      ParallelFilter pf = new ParallelFilter(inputlist,sizeOfFilter,low,high);
      System.out.println("hello");
      ForkJoinPool forkJoinPool = new ForkJoinPool();
      forkJoinPool.invoke(pf);//suspect the problem is here...
      
      for (int i=0; i<pf.outputlist.size();i++){
          
      System.out.println(pf.outputlist.get(i));}
      System.out.println("hey");
      
    }
  catch(Exception e){}
  
 }



  }
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1 回答 1

1

如果你在运行这个程序时输入“hey”，你会得到解析异常，因为空catch块而被忽略。

同样在您的构造函数中，您this.arrayFiltered = arrayFiltered;实际上什么都不做，因为您没有名称为arrayFiltered 的参数。它导致arrayFiltered不会被初始化从而导致 NPE 在arrayFiltered.add(i, inputArray.get(i));

我建议你放入块e.printStackTrace();中catch，它会立即显示所有错误。当然，您需要学习如何使用调试器。

还有这部分

            if (sc.nextLine().length() == 1) {
                continue;
            }
            String[] parts = sc.nextLine().split(" ");

是错的。因为你在这里读了两行。你需要读一次，记住结果然后测试它并解析它。

像这样

            String line = sc.nextLine();
            if (line.length() == 1) {
                continue;
            }
            String[] parts = line.split(" ");
于 2015-08-10T14:40:42.877 回答