这是我写的最小代码,以避免阻塞命令(serve_forever)
我使用 ws4py 作为 websocket 库。
from wsgiref.simple_server import make_server
from ws4py.websocket import WebSocket
from ws4py.server.wsgirefserver import WSGIServer, WebSocketWSGIRequestHandler
from ws4py.server.wsgiutils import WebSocketWSGIApplication
import threading
class TestWebSocket(WebSocket):
def received_message(self, message):
self.send("+OK", False)
class TestServer:
def __init__(self, hostname='127.0.0.1', port=8080):
self.server = make_server(hostname,\
port,\
server_class=WSGIServer,\
handler_class=WebSocketWSGIRequestHandler,\
app=WebSocketWSGIApplication(handler_cls=TestWebSocket)\
)
self.server.initialize_websockets_manager()
self.thread = threading.Thread(target=self.server.serve_forever)
self.thread.start()
print("Server started for {}:{}".format(hostname, str(port)))
def shutdown(self):
self.server.shutdown()