我有一个 Flash 客户端使用 XMLsocket 连接 python 服务器，如下所示：
Security.loadPolicyFile("xmlsocket://*.*.*.*:843");
socket = new XMLSocket();
socket.connect('*.*.*.*', 50000);
socket.send('hello world');
我使用这个 python 脚本来发送安全文件
#security.py
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('0.0.0.0', 843))
s.listen(5)
print('Start...')
def link(sock, addr):
print('Accept new connection from %s:%s...' % addr)
while True:
data = sock.recv(1024)
str = data.decode('utf-8')[:22]
if str=='<policy-file-request/>':
print('!!!!!!!')
sock.send(b'<?xml version="1.0"?>')
sock.send(b'<cross-domain-policy>')
sock.send(b'<allow-access-from domain="*" to-ports="50000" />')
sock.send(b'</cross-domain-policy>\0')
sock.close()
break
print('')
while True:
sock, addr = s.accept()
t = threading.Thread(target=link, args=(sock, addr))
t.start()
并使用它来接收来自客户端的消息：
#server.py
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('0.0.0.0', 50000))
s.listen(5)
print('Waiting for connection...')
def tcplink(sock, addr):
print('Accept new connection from %s:%s...' % addr)
while True:
data = sock.recv(1024)
print(data.decode('utf-8'))
while True:
sock, addr = s.accept()
t = threading.Thread(target=tcplink, args=(sock, addr))
t.start()
当这些脚本运行时，security.py 输出：
Start...
Accept new connection from *.*.*.*....
!!!!!!!
但是 server.py 除了这个之外什么都不输出：
Waiting for connection...
并且闪存的调试也没有输出
似乎flash成功接收了安全文件，但是XMLsocket.connect失败了？