3

我有一个函数，它传递了一个整数列表和所需的行长。假设数据的长度可以被行长度整除。列表中的所有整数都表示字节，因此它们不超过 3 位，并且不小于 0。这是我的函数：

    def pprint(data, rowlen):
    # Prints out the list in a nice grid format
    print '-' * 50
    for index in range(0, len(data), rowlen):
        print data[index:(index+rowlen)]
    print '-' * 50
    return data

输出看起来像这样：

[0, 0, 2, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0, 0]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0, 0, 0, 0, 0, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0]

正如你所看到的，这种工作，但我想要更像这样的东西：

[0  , 0  , 2  , 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  , 0  ]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  , 0  , 0  , 0  , 0  , 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  ]

这样，所有数据都以网格格式对齐，并且很容易看到所有内容的位置。

有没有一种简单的方法可以实现这一点，而不必遍历每个条目并插入空格。

4

1 回答 1

3

使用string.format

    data = [i for i in range(0, 200)]

    def pprint(data, rowlen):
        print '-' * 50
        for index in range(0, len(data), rowlen):
            print ['{:3}'.format(i) for i in data[index:(index+rowlen)]]
        print '-' * 50
        return data

    pprint(data, 10)
于 2015-08-04T13:55:54.317 回答