我的任务是通过用内部数字的破折号替换 3 或更多的内部序列来缩短数字序列(如 3,5,6,7,8,10 将是 3,5-8,10)
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2 回答
2
与上面非常相似,只是使用列表。
<cfscript>
a = listToArray('3,5,6,7,8,10,11,15,16,17,18');
writeOutput( fNumSeries(a) );
string function fNumSeries( array a) output="false" {
var tempList = '';
var outputList = '';
for ( var i in a ) {
if( listLen(tempList) == 0 ) {
// Nothing in the list
tempList = i;
} else if ( listLen(tempList) ) {
if ( listLast(tempList)+1 == i) {
// i is next in order from the previous list item. Just add to temp list.
tempList = listAppend(tempList, i);
} else if (listLen(tempList) >= 3) {
// current item is not the next item, and the tempList is more than 2 items long, so abbreviate and set templist to the current item.
outputList = listAppend(outputList, listFirst(tempList) & '-' & listLast(tempList));
tempList = i;
} else {
// tempList is less than 3 items long, just append to output and set tempList to the current item.
outputList = listAppend(outputList, tempList);
tempList = i;
}
}
}
// Clean up the remaining item(s) in tempList. If 3 or more, abbreviate, else just append to output.
outputList = listLen(tempList) >= 3 ? listAppend(outputList, listFirst(tempList) & '-' & listLast(tempList)) : listAppend(outputList, templist);
return outputList;
}
</cfscript>
于 2015-07-27T18:13:51.267 回答
1
我把下面的函数放在一起,加上一些演示输出。它假设数字是有序的、非重复的数组。(CF 列表函数有助于达到这一点。)有没有更优雅的方法呢?
<cffunction name="fNumSeries" output="1" hint="parses array of numbers for display: 1|2|3|6|7|9|10|11|12 would be 1-3, 6, 7, 9-12 ">
<cfargument name="raNums" required="1" type="array">
<cfset raLen=arraylen(raNums)>
<cfif raLen eq 0><CFRETURN "">
<cfelseif raLen eq 1><CFRETURN raNums[1]>
<cfelseif raLen eq 2><CFRETURN raNums[1] & "," & raNums[2]>
</cfif>
<cfset numSeries="">
<cfset numHold=raNums[1]>
<cfset seqHold=raNums[1]>
<cfset numSeries=raNums[1]><!--- raNums[1]always output the first number --->
<cfloop from="1" to="#raLen#" index="idxItem">
<cfif idxItem gt 1><!--- wait for 2nd element to decide output --->
<cfif numHold+1 neq raNums[idxItem]><!--- reason to output and seqHold+1 neq numHold--->
<cfif seqHold eq numHold>
<cfset numSeries=numSeries & ",#raNums[idxItem]#">
<cfelse>
<cfif seqHold+1 eq numHold><cfset numSeries=numSeries & ","><!--- and numHold+1 neq raNums[1] and seqHold+1 eq numHold --->
<cfelse><cfset numSeries=numSeries & "-">
</cfif>
<cfset numSeries=numSeries & "#numHold#,#raNums[idxItem]#">
</cfif>
<cfset seqHold=raNums[idxItem]>
</cfif>
</cfif>
<cfset numHold=raNums[idxItem]>
</cfloop>
<cfif seqHold neq numHold><!--- display the last element --->
<cfif seqHold+1 eq numHold or raLen eq 2><cfset numSeries=numSeries & ",">
<cfelse><cfset numSeries=numSeries & "-">
</cfif>
<cfset numSeries=numSeries & "#numHold#">
</cfif>
<CFRETURN numSeries>
</cffunction>
<cfset raRa=[
[2,12],
[2,3,12],
[2,4,12],
[2,3,4,12],
[2,8,9,11,12],
[2,9,11,12],
[2,3,8,10,11,12]
]>
<cfoutput>
<cfloop array="#raRa#" index="ra">
#arrayToList(ra)#<br />
#fNumSeries(ra)#<hr>
</cfloop>
</cfoutput>
于 2015-07-27T16:07:23.013 回答