1

好的，脚本现在正在运行，我要感谢所有人的建议。

这是最终的脚本

import smtplib 
import xbmc
import xbmcgui
import datetime

list = ("mary", "james", "tilly")

kb = xbmc.Keyboard('', 'Please type in your name to continue')
kb.doModal()
typedin = kb.getText()

if typedin.lower() in list:
    now = datetime.datetime.now()
    runtime = now.strftime("%Y-%m-%d %H:%M")

    content = xbmc.executebuiltin('kb.getText()')
    mailserver = smtplib.SMTP("smtp.mail.com",25)
    mailserver.ehlo()
    mailserver.starttls()
    mailserver.login('mail@somemail.com','somepwd')
    mailserver.sendmail('mail@somemail.com','mail@somemail.com',typedin + ' has run proggy ' + runtime)
    mailserver.close()
    xbmc.executebuiltin("Notification(An email has been sent, yada yada yada,()")
else:
    xbmc.executebuiltin("THE INPUTTED NAME, IS NOT VALID,()")
    xbmcgui.Dialog().ok(
    "Please try again - User name not correct",
    "The input yada yada",
    "yada yada",
    "yada yada")

所以，只是为了让你知道我正在使用在端口 25 上工作的实时邮件。在 windows 和 linux 和 openelec 上都进行了尝试和测试。工作正常。

4

3 回答 3

2

也许类似于 if 语句的内容？所以只有给出其中一个词，然后做其余的，否则不接受。

list = ["simon", "tom", "sarah", "peter", "jane"]
word = input()
if word.lower() in list:
    print('Ok')
    #continue with rest of program
else:
     print('No, sorry')
于 2015-07-25T11:09:26.807 回答
1

在希望从用户那里获取输入的情况下，最好的做法是使用 raw_input 语句执行 while 循环，例如：

word_list = ['simon', 'tom', 'sarah', 'peter', 'jane', 'sue']

def get_word():
    """returns the word that the user chooses"""
    print("Please choose a name from the following:")
    w_string = ""
    for w in word_list:
        w_string += w + ', '
    #print the word list without a comma at the end.
    print(w_string[:-1])

    while True:
        word = raw_input("\n> ") #use input("\n> ") for python3
        #If you wish to accept something like "SiMoN      " or "S Imon "
        #have the following line:
        word = word.lower().strip()
        if word in word_list:
            return word
        else:
            print("'%s' is not in the list of words. Please choose from the following:\n%s" % (word, w_string[:-1]))

word = get_word()
print(word)
于 2015-07-25T11:31:21.490 回答
0

我最好的选择是不要将列表转换为字符串并检查输入的名称是否在列表中，例如..

import smtplib
import xbmc
import xbmcgui
import datetime

nameList = ["simon", "tom", "sarah", "peter", "jane"]
kb = raw_input('Please type in your name to continue:')

if kb in nameList:
    now = datetime.datetime.now()
    runtime = now.strftime("%Y-%m-%d %H:%M")

    content = xbmc.executebuiltin('kb.getText()')
    mailserver = smtplib.SMTP("smtp.mail.com",25)
    mailserver.ehlo()
    mailserver.starttls()
    mailserver.login('mail@somemail.com','somepwd')
    mailserver.sendmail('mail@somemail.com','mail@somemail.com',typedin + 'has run keymail ' + runtime)
    mailserver.close()
else:
    print ("The Name %s, was not in the list")%kb

并且不要使用 list 和 str 作为变量名。

于 2015-07-27T11:46:08.257 回答