我一直在看这个几个小时,无法弄清楚。如果 heapify 函数中的比较更改为大于,则输出按应有的递增顺序排列。我希望我的列表按降序排序,但它没有使用以下代码给出正确的输出:
#include <stdlib.h>
#include <stdio.h>
#include <string.h>
typedef struct stuff {
char *str;
}stuff_t;
void heapify(stuff_t *stuff_array, int i, int n)
{
stuff_t temp;
int left, right, max;
left = 2*i;
right = left + 1;
max = i;
if (left < n)
if (strtod(stuff_array[left].str, NULL) < strtod(stuff_array[i].str, NULL))
max = left;
if (right < n)
if (strtod(stuff_array[right].str, NULL) < strtod(stuff_array[max].str, NULL))
max = right;
if (max != i)
{
temp = stuff_array[i];
stuff_array[i] = stuff_array[max];
stuff_array[max] = temp;
heapify(stuff_array, max, n);
}
}
void heapsort(stuff_t *stuff_array)
{
short i,N;
stuff_t temp;
N = 0;
while (stuff_array[N].str)
N++;
for (i = (N/2)-1; i >= 0; i--)
heapify(stuff_array, i, N);
for (i = N-1; i >= 1; i--) {
temp = stuff_array[0];
stuff_array[0] = stuff_array[i];
stuff_array[i] = temp;
heapify(stuff_array, 0, i);
}
}
int main (int argc, char* argv[])
{
int i;
stuff_t *s_list = calloc(4, sizeof(stuff_t));
stuff_t *s_list1 = calloc(8, sizeof(stuff_t));
s_list[0].str = "9.3";
s_list[1].str = "9.3";
s_list[2].str = "7.8";
printf("before: ");
for (i = 0; i < 3; i++)
printf("%s, ", s_list[i]);
printf("\n");
heapsort(s_list);
printf("after: ");
for (i = 0; i < 3; i++)
printf("%s, ", s_list[i]);
printf("\n");
s_list1[0].str = "7.5";
s_list1[1].str = "10.0";
s_list1[2].str = "10.0";
s_list1[3].str = "8.3";
s_list1[4].str = "6.5";
s_list1[5].str = "5.0";
s_list1[6].str = "4.6";
printf("before: ");
for (i = 0; i < 3; i++)
printf("%s, ", s_list1[i]);
printf("\n");
heapsort(s_list1);
printf("after: ");
for (i = 0; i < 7; i++)
printf("%s, ", s_list1[i]);
printf("\n");
return 0;
}
程序输出:
// using less than comparison
before: 9.3, 9.3, 7.8,
after: 9.3, 7.8, 9.3,
before: 7.5, 10.0, 10.0,
after: 10.0, 10.0, 8.3, 7.5, 6.5, 4.6, 5.0,
// using greator than comparison
before: 9.3, 9.3, 7.8,
after: 7.8, 9.3, 9.3,
before: 7.5, 10.0, 10.0,
after: 4.6, 5.0, 6.5, 7.5, 8.3, 10.0, 10.0,