1

我正在尝试使用 NSUserDefaults 快速保存一个字符串数组。我四处搜索并相信我必须使用 [NSString] 而不是 [String] 但是应用程序仍然因错误而崩溃

致命错误：在展开可选值时意外发现 nil

我看不出我做错了什么，因为它可以很好地保存整数和字符串。这是我的数据单例和 NSUserDefaults 的代码。

struct DefaultsKeys
{
  static let myString  = "myString"
  static let myInt  = "myInt"
  static let myArray = "myArray"

}



class DataContainerSingleton
{
  static let sharedDataContainer = DataContainerSingleton()


  var myString: String?
  var myInt: Int?
  var myArray:[NSString]?

/* I have also tried:
  var myArray:[NSString] = [NSString]() */



  var goToBackgroundObserver: AnyObject?

  init()
  {
    let defaults = NSUserDefaults.standardUserDefaults()


    myString = defaults.objectForKey(DefaultsKeys.myString) as! String?
    myInt = defaults.objectForKey(DefaultsKeys.myInt) as! Int?
    myArray = defaults.objectForKey(DefaultsKeys.myArray) as! [NSString]?



    goToBackgroundObserver = NSNotificationCenter.defaultCenter().addObserverForName(
      UIApplicationDidEnterBackgroundNotification,
      object: nil,
      queue: nil)
      {
        (note: NSNotification!) -> Void in
        let defaults = NSUserDefaults.standardUserDefaults()

        defaults.setObject( self.myString, forKey: DefaultsKeys.my)
        defaults.setObject( self.myInt, forKey: DefaultsKeys.myInt)
        defaults.setObject( self.myArray, forKey: DefaultsKeys.myArray)


        defaults.synchronize()
    }
  }
}
4

2 回答 2

2 
        <!-- language: swift -->

        //declare and initiate the array        
        var sample_array : NSMutableArray! = []
        //use mutable array to add data

        //variable to store value in array
        var say: String! =  "Hello"

        //add values in array
        sample_array.addObject("hello")
        //or
        //sample_array.addObject(say)

        /*
        //you can also save values in array like this
        var sample_array: Array<String> = []
        var say: String! =  "Hello"
        sample_array = ["Qwerty"]
        sample_array.insert(say, atIndex: 1)
        println(sample_array)
        */

        //archive and saving data 
        let data = NSKeyedArchiver.archivedDataWithRootObject(sample_array)
        NSUserDefaults.standardUserDefaults().setObject(data, forKey: "array_key")
        NSUserDefaults.standardUserDefaults().synchronize()

        //unarchive and getting data
        if let data = NSUserDefaults.standardUserDefaults().objectForKey("array_key") as? NSData {
        stopover_array = NSKeyedUnarchiver.unarchiveObjectWithData(data)  as NSMutableArray
            }
于 2015-08-19T05:42:31.470 回答
1

问题是代码：

myString = defaults.objectForKey(DefaultsKeys.myInt) as! String?
myInt = defaults.objectForKey(DefaultsKeys.myInt) as! Int?
myArray = defaults.objectForKey(DefaultsKeys.myArray) as! [NSString]?

as!意味着打开一个可选值，这就是你的应用程序因错误而崩溃的原因

fatal error: unexpectedly found nil while unwrapping an Optional value

如果defaults.objectForKey(DefaultsKeys.myInt)为 nil，则不允许展开 nil。你应该使用

myString = defaults.objectForKey(DefaultsKeys.myInt) as? String

反而。

于 2015-07-23T05:01:30.817 回答