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我想将我的小程序中生成的私钥-公钥对 (ECDSA) 的公钥发送到主机应用程序/终端。

在 RSA 中，我通常会发送模数和指数，并在主机端生成公钥。

在 ECDSA 中，我从链接中读到，如果您将 W 参数字节放在卡外，我们可以做同样的事情点击这里：Stackoverflow 答案：在 Java 上编码公钥

我现在有卡中的 W 个字节。有人可以建议如何从中创建公钥吗？

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我编写了这个方法来将 EC 公钥转换为java.security.interfaces.ECPublicKey密钥对象。为此，我使用 Bouncy Castle 提供程序 ( bcprov-ext-jdk16-1.46.jar)。您可以从这里下载最新版本。

/**
 * This method converts the EC public key (ECPublicKey#getW()) into ECPublicKey
 * @param cardPublicKey as W
 * @param curveName (for example "P-224")
 * @return java.security.interfaces.ECPublicKey
 */
public ECPublicKey ucPublicKeyToPublicKey(byte[] cardPublicKey, String curveName) {
    //for example curveName = "P-224";
    java.security.interfaces.ECPublicKey ecPublicKey = null; // java.security.interfaces.ECPublicKey
    java.security.KeyFactory kf = null;

    org.bouncycastle.jce.spec.ECNamedCurveParameterSpec ecNamedCurveParameterSpec = ECNamedCurveTable.getParameterSpec(curveName);
    org.bouncycastle.math.ec.ECCurve curve = ecNamedCurveParameterSpec.getCurve();
    java.security.spec.EllipticCurve ellipticCurve = EC5Util.convertCurve(curve, ecNamedCurveParameterSpec.getSeed());
    java.security.spec.ECPoint ecPoint = ECPointUtil.decodePoint(ellipticCurve, cardPublicKey);
    java.security.spec.ECParameterSpec ecParameterSpec = EC5Util.convertSpec(ellipticCurve, ecNamedCurveParameterSpec);
    java.security.spec.ECPublicKeySpec publicKeySpec = new java.security.spec.ECPublicKeySpec(ecPoint, ecParameterSpec);

    try {
        kf = java.security.KeyFactory.getInstance("EC", "BC");
    } catch (Exception e) {
        System.out.println("Caught Exception kf : " + e.toString());
    }

    try {
        ecPublicKey = (ECPublicKey) kf.generatePublic(publicKeySpec);
    } catch (Exception e) {
        System.out.println("Caught Exception public key: " + e.toString());
    }

    return ecPublicKey;
}
于 2015-07-08T18:51:30.020 回答