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CREATE TABLE `fitness_pledges` (
    `ID` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
    `first_name` VARCHAR(250) NOT NULL,
    `last_name` VARCHAR(250) NOT NULL,
    `email` VARCHAR(100) NOT NULL,
    `token` BIGINT(20) UNSIGNED NOT NULL,
    `email_valid` TINYINT(1) UNSIGNED NOT NULL DEFAULT '0',
    `entered_sweeps` TINYINT(1) UNSIGNED NOT NULL DEFAULT '0',
    `referrals` INT(10) UNSIGNED NOT NULL DEFAULT '0',
    PRIMARY KEY (`ID`),
    UNIQUE INDEX `email` (`email`),
    UNIQUE INDEX `token` (`token`)
)
COMMENT='holds validation token, first name, last name, email address, number of referrals and whether sweepstakes was entered\r\n'
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
;

CREATE TABLE `finess_referrals` (
    `ID` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
    `first_name` VARCHAR(250) NOT NULL,
    `last_name` VARCHAR(250) NOT NULL,
    `email` VARCHAR(100) NOT NULL,
    `token` BIGINT(20) UNSIGNED NOT NULL,
    `referral_token` BIGINT(20) UNSIGNED NOT NULL,
    `referral_validated` TINYINT(4) NOT NULL DEFAULT '0',
    PRIMARY KEY (`ID`),
    INDEX `token_FK` (`token`),
    INDEX `referral_token_FK` (`referral_token`),
    CONSTRAINT `referral_token_FK` FOREIGN KEY (`referral_token`) REFERENCES `fitness_pledges` (`token`) ON DELETE NO ACTION,
    CONSTRAINT `token_FK` FOREIGN KEY (`token`) REFERENCES `fitness_pledges` (`token`) ON DELETE NO ACTION
)
COMMENT='holds the first name, last name, email and validation token of the referrer as well as the token of the referred individual and a flag for whether the referred individual\'s email has been validated'
COLLATE='latin1_swedish_ci'
ENGINE=InnoDB
;

这个由 HeidiSQL 生成的 Alter Table 尝试为组合的 first_name、last_name 和 email 字段添加外键失败，外键约束形成不正确。字段都定义相同，排序规则相同。为什么会失败？

ALTER TABLE `finess_referrals`
ADD CONSTRAINT `first_last_email_FK` FOREIGN KEY (`first_name`, `last_name`, `email`) 
REFERENCES `fitness_pledges` (`first_name`, `last_name`, `email`) ON DELETE NO ACTION;
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2 回答 2

1

fitness_pledges您首先需要表中的索引(first_name, last_name, email)。从使用外键约束：

MySQL 需要外键和引用键上的索引，以便外键检查可以快速且不需要表扫描。

如有必要，它将自动在引用表中创建索引，但不会为引用表创建索引。

所以你需要这样做：

CREATE INDEX first_last_email ON fitness_pledges (first_name, last_name, email);
于 2015-07-06T22:02:32.190 回答
0

根据 SQL 标准，外键必须引用父表的主键或唯一键。如果主键有多个列，外键必须有相同的列数和顺序

于 2015-07-06T22:04:01.257 回答