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我正在使用我编写的 .plt 文件访问来自许多不同文件的数据。只有每个数据集的特定域是重要的。我试图仅将每个数据集的特定域绘制到一个图表上。

每个域中的数据对应一个峰值。我想绘制每个峰值，然后将指数衰减函数拟合到峰值。

这是我的绘图文件中的代码：

set xlabel "Time (ms)"
set ylabel "voltage"

set title "T1 time for Isopropyl Alcohol"
dir='C:\Users\Daniel\Desktop\College\modern lab\gp501-win64-mingw\gnuplot\bin\data files\isoproply_alc_t1\'
unset key
set style data linespoints
x(v, left, right) = (v >= left && v <= right ? v : 1/0)
plot dir.'nmr-t1-isopropyl-dt10' using (x($0*0.01, 3, 7)):1, \
     dir.'nmr-t1-isopropyl-dt50' using (x($0*0.01, 20, 40)):1, \
     dir.'nmr-t1-isopropyl-dt100' using (x($0*0.01, 40, 60)):1, \
     dir.'nmr-t1-isopropyl-dt150' using (x($0*0.01, 70, 80)):1, \
     dir.'nmr-t1-isopropyl-dt200' using (x($0*0.01, 99, 101)):1, \
     dir.'nmr-t1-isopropyl-dt230' using (x($0*0.01, 114, 116)):1, \
     dir.'nmr-t1-isopropyl-dt250' using (x($0*0.01, 124, 126)):1, \
     dir.'nmr-t1-isopropyl-dt270' using (x($0*0.01, 134, 136)):1, \
     dir.'nmr-t1-isopropyl-dt290' using (x($0*0.01, 144, 146)):1, \
     dir.'nmr-t1-isopropyl-dt300' using (x($0*0.01, 149, 151)):1, \
     dir.'nmr-t1-isopropyl-dt320' using (x($0*0.01, 159, 161)):1, \
     dir.'nmr-t1-isopropyl-dt340' using (x($0*0.01, 169, 171)):1, \
     dir.'nmr-t1-isopropyl-dt360' using (x($0*0.01, 178, 183)):1, \
     dir.'nmr-t1-isopropyl-dt400' using (x($0*0.01, 198, 201)):1, \
     dir.'nmr-t1-isopropyl-dt430' using (x($0*0.01, 213, 217)):1, \
     dir.'nmr-t1-isopropyl-dt470' using (x($0*0.01, 233, 236)):1, \
     dir.'nmr-t1-isopropyl-dt580' using (x($0*0.01, 289, 291)):1, \
     dir.'nmr-t1-isopropyl-dt620' using (x($0*0.01, 309, 311)):1, \
     dir.'nmr-t1-isopropyl-dt650' using (x($0*0.01, 324, 326)):1, \
     dir.'nmr-t1-isopropyl-dt700' using (x($0*0.01, 348, 352)):1, \
     dir.'nmr-t1-isopropyl-dt750' using (x($0*0.01, 374, 376)):1, \
     dir.'nmr-t1-isopropyl-dt800' using (x($0*0.01, 399, 401)):1, \
     dir.'nmr-t1-isopropyl-dt850' using (x($0*0.01, 424, 426)):1, \
     dir.'nmr-t1-isopropyl-dt900.2' using (x($0*0.01, 449.5, 451)):1

这给出了正确的域。

现在我想在 y 轴上翻转数据点，过去一些任意 x 值。我想让他们消极。

我尝试了该flipy命令，但这不起作用。

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1 回答 1

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Gnuplot 不支持在单个plot命令中为每个数据文件指定单独的范围。这仅适用于功能。

您必须通过为所需范围之外的所有点提供使相应点无效的值来过滤using语句中的数据：1/0

left = 3
right = 7
plot 'file.dat' using ($0 > left && $0 < right ? $0 : 1/0):1

为了使命令更具可读性，您还可以将过滤放在一个函数中。还有其他一些方法可以提高代码的可读性：

  • 定义一个dir包含文件路径的变量。然后由操作员将数据文件名与此变量连接.：

    dir = 'C:\my path\'
plot dir.'file.dat' ...

  • 跳过键（图例）可以在全局范围内跳过unset key

  • 您可以使用全局设置数据文件的绘图样式set style data linespoints

所以你的脚本可能看起来像

set xlabel "Time (ms)"
set ylabel "voltage"
set format y "%s"

set title "T1 time for Isopropyl Alcohol"
dir='C:\Users\Daniel\Desktop\College\modern lab\gp501-win64-mingw\gnuplot\bin\data files\isoproply_alc_t1\'
unset key
set style data linespoints
x(v, left, right) = (v >= left && v <= right ? v : 1/0
plot dir.'nmr-t1-isopropyl-dt10' using (x($0*0.01, 3, 7)):1, \
     dir.'nmr-t1-isopropyl-dt50' using (x($0*0.01, 20, 40)):1, \
     dir.'nmr-t1-isopropyl-dt100' using (x($0*0.01, 40, 60)):1, \
     dir.'nmr-t1-isopropyl-dt150' using (x($0*0.01, 70, 80)):1
于 2015-06-27T21:04:25.803 回答