所以这里有一些代码可以简化我一直在做的事情:
vars = {
'a':'alice',
'b':'bob',
}
cnames = ['charlie', 'cindy']
commands = []
for c in cnames:
kwargs = dict(vars)
kwargs['c'] = c
print kwargs
commands.append(lambda:a_function(**kwargs))
print commands
def a_function(a=None, b=None, c=None):
print a
print b
print c
for c in commands:
print "run for "+ repr(c)
c()
这是它的输出:
{'a': 'alice', 'c': 'charlie', 'b': 'bob'}
{'a': 'alice', 'c': 'cindy', 'b': 'bob'}
[<function <lambda> at 0x1001e9a28>, <function <lambda> at 0x1001e9e60>]
run for <function <lambda> at 0x1001e9a28>
alice
bob
cindy
run for <function <lambda> at 0x1001e9e60>
alice
bob
cindy
我希望得到 charlie,然后是 cindy,为什么 cindy 会显示两次?