在回答这个问题时,我认为编写一个 VBE 宏会自动替换看起来像的行会很有趣
DimAll a, b, c, d As Integer
经过
Dim a As Integer, b As Integer, c As Integer, d As Integer
在我的初稿中,我只想修改一个选定的行。在建立适当的引用以获取 VBE 对象模型(请参阅http://www.cpearson.com/excel/vbe.aspx)并玩了一下之后,我想出了:
Function ExpandDim(codeLine As String) As String
Dim fragments As Variant
Dim i As Long, n As Long, myType As String
Dim last As Variant
Dim expanded As String
If UCase(codeLine) Like "*DIMALL*AS*" Then
codeLine = Replace(codeLine, "dimall", "Dim", , , vbTextCompare)
fragments = Split(codeLine, ",")
n = UBound(fragments)
last = Split(Trim(fragments(n)))
myType = last(UBound(last))
For i = 0 To n - 1 'excludes last fragment
expanded = expanded & IIf(i = 0, "", ",") & fragments(i) & " As " & myType
Next i
expanded = expanded & IIf(n > 0, ",", "") & fragments(n)
ExpandDim = expanded
Else
ExpandDim = codeLine
End If
End Function
Sub DimAll()
Dim myVBE As VBE
Dim startLine As Long, startCol As Long
Dim endLine As Long, endCol As Long
Dim myLine As String
Set myVBE = Application.VBE
myVBE.ActiveCodePane.GetSelection startLine, startCol, endLine, endCol
myLine = myVBE.ActiveCodePane.CodeModule.Lines(startLine, 1)
Debug.Print ExpandDim(myLine)
myVBE.ActiveCodePane.CodeModule.ReplaceLine startLine, ExpandDim(myLine)
End Sub
在另一个代码模块中,我有:
Sub test()
DimAll a, b, c, d As Integer
Debug.Print TypeName(a)
Debug.Print TypeName(b)
Debug.Print TypeName(c)
Debug.Print TypeName(d)
End Sub
这是奇怪的部分。当我突出显示以 DimAll a 开头的行并调用我笨拙的子 DimAll 时,在即时窗口中我看到
Dim a As Integer, b As Integer, c As Integer, d As Integer
正如预期的那样,但在代码模块本身中,该行更改为
Dim a, b, c, d As Integer
DimAll 已被 Dim 取代——但该行的其余部分未修改。我怀疑逗号混淆了 ReplaceLine 方法。关于如何解决这个问题的任何想法?