0

非常感谢那些回复。SQL Server 中是否有一种方法可以从 table1 中获取数据并像 table2 一样输出数据?

谢谢!

表格1:

+---------+-----------+----------+------------------+
|  Name   |    DOB    | Agent ID |    Agent Name    |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Smith            |  
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | John             |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Larry            |
+---------+-----------+----------+------------------+

表2:

+---------+-----------+----------+------------------+
|  Name   |    DOB    | Agent ID |    Agent Name    |
+---------+-----------+----------+------------------+
| subject | 4/20/1960 | 4444     | Smith,John,Larry |
+---------+-----------+----------+------------------+
4

2 回答 2

2

对于 SQL Server 2005+,使用 STUFF & FOR XML PATH 创建一个逗号分隔的列表:

SELECT DISTINCT
       t.name,
       t.dob,
       t.agentid,
       STUFF(ISNULL(SELECT ', ' + x.agentname
                      FROM TABLE1 x
                     WHERE x.agentid = t.agentid
                  GROUP BY x.agentname
                   FOR XML PATH ('')), ''), 1, 2, '')
  FROM TABLE1 t
于 2010-06-23T00:58:55.140 回答
1
选择不同的 t.Name、t.DOB、t.AgentID、x.AgentName
从表 1 t
交叉应用(当 ROW_NUMBER() OVER 时选择案例(按 AgentName 排序)= 1
                         THEN '' ELSE ', ' END + AgentName
             从表 1
             WHERE AgentID = t.AgentID
             AND AgentName 不为空
             FOR XML PATH(''))x(AgentName)
于 2010-06-23T02:19:22.967 回答