51

以下是我遇到问题的代码：

func parseFeedForRequest(request: NSURLRequest, callback: (feed: RSSFeed?, error: NSError?) -> Void)
{
    NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) { (response, data, error) -> Void in

        if ((error) != nil)
        {
            callback(feed: nil, error: error)
        }
        else
        {
            self.callbackClosure = callback

            let parser : NSXMLParser = NSXMLParser(data: data!)
            parser.delegate = self
            parser.shouldResolveExternalEntities = false
            parser.parse()
        }
    }
}

从 iOS 9 开始，现在已弃用，并告诉我改用 dataTaskWithRequest。有人可以帮我用 dataTask 更改 sendAsync，我不知道该怎么做。

4

10 回答 10

85

改用NSURLSession如下所示，

对于 Objective-C

NSURLSession *session = [NSURLSession sharedSession];
[[session dataTaskWithURL:[NSURL URLWithString:"YOUR URL"]
          completionHandler:^(NSData *data,
                              NSURLResponse *response,
                              NSError *error) {
            // handle response

  }] resume];

对于斯威夫特，

    var request = NSMutableURLRequest(URL: NSURL(string: "YOUR URL")!)
    var session = NSURLSession.sharedSession()
    request.HTTPMethod = "POST"

    var params = ["username":"username", "password":"password"] as Dictionary<String, String>

    request.HTTPBody = try? NSJSONSerialization.dataWithJSONObject(params, options: [])

    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

    var task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
        print("Response: \(response)")})

    task.resume()

对于异步查询，来自 Apple文档

与大多数网络 API 一样，NSURLSession API 是高度异步的。它以两种方式之一返回数据，具体取决于您调用的方法：

当传输成功完成或出现错误时，将数据返回到您的应用程序的完成处理程序块。

通过在接收到数据时调用自定义委托上的方法。

通过在下载到文件完成时调用自定义委托上的方法。

于 2015-06-19T10:07:27.343 回答
16

快速实施

let session = NSURLSession.sharedSession()
session.dataTaskWithRequest(request) { (data, response, error) -> Void in

}
于 2015-06-19T10:29:09.947 回答
10

斯威夫特 3.0

var request = URLRequest(url: URL(string: "http://example.com")!)
request.httpMethod = "POST"
let session = URLSession.shared

session.dataTask(with: request) {data, response, err in
    print("Entered the completionHandler")
}.resume()
于 2016-08-08T05:23:48.730 回答
9

这是 swift 2.1 版本：

let request = NSMutableURLRequest(URL: NSURL(string: "YOUR URL")!)
let session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"

let params = ["username":"username", "password":"password"] as Dictionary<String, String>

request.HTTPBody = try! NSJSONSerialization.dataWithJSONObject(params, options: [])
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")

let task = session.dataTaskWithRequest(request, completionHandler: {data, response, error -> Void in
print("Response: \(response)")})

task.resume()
于 2015-09-27T07:26:52.617 回答
4

斯威夫特 2.0：

旧的（以下替换为新的）：

NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue()) { (response, data, error) -> Void in

// Code

}

新的：

let task = NSURLSession.sharedSession().dataTaskWithRequest(request){ data, response, error in

// Code

}
task.resume()
于 2016-02-09T01:13:02.863 回答
2

斯威夫特 4

let params = ["email":"email@email.com", "password":"123456"] as Dictionary<String, String>

var request = URLRequest(url: URL(string: "http://localhost:8080/api/1/login")!)
request.httpMethod = "POST"
request.httpBody = try? JSONSerialization.data(withJSONObject: params, options: [])
request.addValue("application/json", forHTTPHeaderField: "Content-Type")

let session = URLSession.shared
let task = session.dataTask(with: request, completionHandler: { data, response, error -> Void in

    do {
        let json = try JSONSerialization.jsonObject(with: data!) as! Dictionary<String, AnyObject>
        print(json)
    } catch {
        print("error")
    }

})

task.resume()
于 2017-10-23T17:55:14.803 回答
1

用 Swift 3.1

let request = NSMutableURLRequest(url: NSURL(string: image_url_string)! as URL)
    let session = URLSession.shared
    request.httpMethod = "POST"

    let params = ["username":"username", "password":"password"] as Dictionary<String, String>

    request.httpBody = try? JSONSerialization.data(withJSONObject: params, options: [])

    request.addValue("application/json", forHTTPHeaderField: "Content-Type")
    request.addValue("application/json", forHTTPHeaderField: "Accept")

    let task = session.dataTask(with: request as URLRequest, completionHandler: {data, response, error -> Void in
        print("Response: \(String(describing: response))")})

    task.resume()
于 2017-07-04T07:40:15.973 回答
0

这是带有 JSONSerialised 数据的Nilesh Patel 答案的 SWIFT3.0 版本

let url = URL(string: "<HERE GOES SERVER API>")!
            var request = URLRequest(url: url)
            request.httpMethod = "POST" //GET OR DELETE etc....
            request.setValue("application/json", forHTTPHeaderField: "Content-Type")
            request.setValue("<ValueforAuthorization>", forHTTPHeaderField: "Authorization")
            let parameter = [String:Any]() //This is your parameters [String:Any]
            do {
                let jsonData = try JSONSerialization.data(withJSONObject: parameter, options: .prettyPrinted)
                // here "jsonData" is the dictionary encoded in JSON data
                request.httpBody = jsonData
                let session = URLSession(configuration: .default)
                let task = session.dataTask(with: request, completionHandler: { (incomingData, response, error) in
                    if let error = error {
                        print(error.localizedDescription)
                        print(request)
                    }else if let response = response {
                        print(response)
                    }else if let incomingData = incomingData {
                        print(incomingData)
                    }
                })
                task.resume()

            } catch {
                print(error.localizedDescription)
            }
于 2017-02-23T11:02:09.170 回答
0

举例说明，弃用以下代码的替代代码：

sendAsynchronousRequest(_:queue:completionHandler:)' 在 iOS 9.0 中已弃用：使用 [NSURLSession dataTaskWithRequest:completionHandler:]

经过测试并在 Swift 2.1 及更高版本中工作。

import UIKit

class ViewController: UIViewController {


    @IBOutlet var theImage: UIImageView!


    override func viewDidLoad() {
        super.viewDidLoad()


        let url = NSURL(string: "https://upload.wikimedia.org/wikipedia/commons/6/6a/Johann_Sebastian_Bach.jpg")


        let task = NSURLSession.sharedSession().dataTaskWithURL(url!) { (data, response, error) -> Void in

            if error != nil {
                print("thers an error in the log")
            } else {

                dispatch_async(dispatch_get_main_queue()) {
                let image = UIImage(data: data!)
                self.theImage.image = image

                }
            }

        }

        task.resume()

    }

}

//在 ViewControllers ImageView 上显示图像。连接 ImageView 的插座

于 2015-12-24T10:59:07.060 回答
0

斯威夫特 4.2

这对我有用：

func loadImageFromURL(URL: NSURL) {
    let request = URLRequest(url: URL as URL)
    let task = URLSession.shared.dataTask(with: request) { (data, response, error) in
        if let imageData = data {
            DispatchQueue.main.async {
                self.imageView.image = UIImage(data: imageData)
            }
        }
    }
    task.resume()
}

我不得不添加“DispatchQueue.main.async {}”，因为我有一个运行时警告，因为只有主线程应该修改 UI 元素。

于 2018-07-01T07:06:25.690 回答