我的问题是使用 CUDA 找出 n 维球体中的整数点数。我不明白下面的代码有什么问题,但它一直给出 0 输出。CUDA 计算能力为 2.0,工具包版本为 3.10。感谢所有的帮助。
__global__ void count_in(int pow_rad, int ndim,int *digit,int w,unsigned int *count,double radius)
{
long int i,j;
int rem,idx,sq,num;
int iy=blockDim.y * blockIdx.y + threadIdx.y;
int ix=blockDim.x * blockIdx.x + threadIdx.x;
int width=gridDim.x*blockDim.x;
int h=2*w+1;
i=iy*width+ix;
if(i>pow_rad) return;
sq=0;
idx=0;
num=i;
for(j=0;j<ndim;j++)
{digit[j]=0;}
while(num!=0)
{
rem=num%w;
num/=w;
digit[idx]=rem;
idx++;
}
for(j=0;j<ndim;j++)
{sq+=(digit[j]-h)*(digit[j]-h);}
if(sq<(radius*radius))
atomicInc(count,(unsigned int)1);
__syncthreads();
}
int main(int argc, char* argv[])
{
const long ntrials = 5;
int i;
for (int n = 0; n < ntrials; ++n) {
int *digit;
unsigned int *count;
std::cout<<n<<std::endl;
int pow_rad;
unsigned int num;
// Select radius and number of dimensions at random
const double r = drand48() * (RMAX - RMIN) + RMIN;
const int nd = lrand48() % (MAXDIM - 1) + 1;
cudaMalloc((void**) &digit,sizeof(int)*nd);
cudaMalloc((void**) &count,sizeof(unsigned int));
cudaMemset(count,0,sizeof(unsigned int));
int h=(int)floor(r);
int w=2*h+1;
std::cout << "###"<< r <<" "<< nd<< std::endl;
for(i=1;i<=nd;i++)
pow_rad*=w;
int width=(int)sqrt(pow_rad);
// Call your function
dim3 dimBlock(32,32);
dim3 dimGrid((width/32)+1,(width/32)+1);
count_in<<<dimGrid,dimBlock>>>(pow_rad, nd,digit,w,count,r);
cudaMemcpy(&num,count,sizeof(unsigned int),cudaMemcpyDeviceToHost);
std::cout << "-->"<<num << std::endl;
}
}