我想从列表视图转到详细视图,因此,我OnClickListener
在列表中使用以下内容:
@Override
public void onClick(View view)
{
Bet bet = (Bet)view.getTag();
FragmentManager fm = getActivity().getSupportFragmentManager();
BetDetailFragment f = BetDetailFragment.create(bet);
String tag = f.getClass().getName();
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP)
{
setSharedElementReturnTransition(TransitionInflater.from(getActivity()).inflateTransition(android.R.transition.move));
f.setSharedElementEnterTransition(TransitionInflater.from(getActivity()).inflateTransition(android.R.transition.move));
}
FragmentTransaction ft = fm.beginTransaction()
.replace(R.id.frame_container, f, tag)
.addToBackStack(tag);
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP)
{
L.d(this, "TRANS: " + TransitionUtil.getTransitionNameBetLogo1(bet) + "|" + view.findViewById(R.id.ivLogo1));
L.d(this, "TRANS: " + TransitionUtil.getTransitionNameBetLogo2(bet) + "|" + view.findViewById(R.id.ivLogo2));
ft.addSharedElement(view.findViewById(R.id.ivLogo1), "1");//TransitionUtil.getTransitionNameBetLogo1(bet));
ft.addSharedElement(view.findViewById(R.id.ivLogo2), "2");//TransitionUtil.getTransitionNameBetLogo2(bet));
}
ft.commit();
}
我的函数返回唯一的名称,我有两个不同的视图,但它仍然不起作用。我已经注释掉了不必要的函数,并在其中手动写了一些唯一的事务名称......但是,我仍然在第一行中得到了这个异常addSharedElement
:
java.lang.IllegalArgumentException: Unique transitionNames are required for all sharedElements
at android.support.v4.app.BackStackRecord.addSharedElement
编辑
没有共享元素,一切都运行良好......