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我希望能够按接口然后按 inet 地址对 ifconfig 的输出进行分组。另外请假设接口块之间没有空格。

eth0      Link encap:Ethernet  HWaddr 52:54:00:12:34:56
          inet addr:10.0.2.15  Bcast:10.0.2.255  Mask:255.255.255.0
          inet6 addr: fe80::5054:ff:fe12:3456/64 Scope: Link
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:1382 errors:0 dropped:0 overruns:0 frame:0
          TX packets:1344 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000
          RX bytes:247209 TX bytes:131216
          Interrupt:9 Base address:0xc000
lo        Link encap:Local Loopback
          inet addr:127.0.0.1  Mask:255.0.0.0
          inet6 addr: ::1/128 Scope: Host
          UP LOOPBACK RUNNING  MTU:16436  Metric:1
          RX packets:1400 errors:0 dropped:0 overruns:0 frame:0
          TX packets:1400 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:0
          RX bytes:109731 TX bytes:109731
wlan0     Link encap:Ethernet  HWaddr CC:FA:00:A9:1D:7C
          inet addr:10.92.70.35  Bcast:10.92.71.255  Mask:255.255.252.0
          inet6 addr: 2001:4898:4070:101b:cefa:ff:fea9:1d7c/64 Scope: Global
          inet6 addr: fe80::cefa:ff:fea9:1d7c/64 Scope: Link
          inet6 addr: 2001:4898:4070:101b:1d4e:9b7f:f197:2e6f/64 Scope: Global
          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
          RX packets:134563 errors:0 dropped:0 overruns:0 frame:0
          TX packets:41967 errors:0 dropped:0 overruns:0 carrier:0
          collisions:0 txqueuelen:1000
          RX bytes:75871586 TX bytes:9616476

将产生 3 个组，我可以参考并确定它们是否以ethor开头，wlan然后inet addr从每个组中取出

到目前为止，我必须@"inet addr:(?<IpV4Address>((25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?))"获得 inet 地址，但我还没有弄清楚如何将接口块分开。

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1 回答 1

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这是一种更好的方法：通过确定默认接口$ route并找到接口，Destination = default然后执行您确定的接口$ ifconfig default_interface在哪里。这样只有一个接口块，您可以轻松解析default_interface$ routeinet addr

于 2015-06-10T21:23:48.983 回答