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我在我的服务器中调用一个函数并且应用程序崩溃了,但它在模拟器上运行良好。我的代码:

class func changeTweet(tweet:String)
{
let data = NSMutableData()
let urlPath: String = "http://127.0.0.1:5000/registerword?word=\(tweet)"
let url: NSURL = NSURL(string: urlPath)!
var request = NSMutableURLRequest(URL: url)
let request1: NSURLRequest = NSURLRequest(URL: url)
let response: AutoreleasingUnsafeMutablePointer<NSURLResponse?
>=nil

//crashes on this line:
let dataVal: NSData = try! NSURLConnection.sendSynchronousRequest(request1, returningResponse: response) 

var err: NSErrorPointer
let string = NSString(data: dataVal, encoding: NSUTF8StringEncoding)
if let str = string
{
  print("Server Response: \(str)")
}
}

PS:我已经在plist上添加了密钥

4

1 回答 1

1

尝试这个:

让数据:NSData = 试试!NSURLConnection.sendSynchronousRequest(request, returnedResponse: &response)

我认为这是您需要的响应前面的 &。

于 2015-06-11T03:54:21.357 回答