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如何修改我@SQLUpdate的以将Joda DateTime对象转换为h2可读的时间戳？

我有一个MyDao带有insert方法的 DAO 对象。

public interface MyDao extends Transactional<MyDao> {
    @SqlUpdate(
        "INSERT INTO my_table "(id, original_date, later_date)" +
        "VALUES (:id, :originalDate, :laterDate)"
    void insert(@BindBean MyObject myObject);
}

这里是MyObject：

import java.util.UUID;
import org.joda.time.DateTime;

public class MyObject {
    private UUID id;
    private DateTime originalDate;
    private DateTime laterDate;

    public MyObject(UUID id, DateTime originalDate, DateTime laterDate) {
        this.id = id;
        this.originalDate = originalDate;
        this.laterDate = laterDate;
    }

}

在migrations.xml文件中（我正在使用http://www.liquibase.org/xml/ns/dbchangelog），我有：

<column name="original_date" type="timestamp">
    <constraints nullable="false"/>
</column>
<column name="later_date" type="timestamp">
    <constraints nullable="false"/>
</column>

这是我的测试：

@Test
public void test() {
    DateTime dt = new DateTime(2015, 5, 29, 8, 34);
    UUID uuid = new UUID(5, 8);
    MyObject myObject = new MyObject(uuid, dt, dt);
    mydao.insert(myObject)
    // assertEquals and other code here
}

我试图对此进行测试，但出现如下错误：

org.skife.jdbi.v2.exceptions.UnableToExecuteStatementException: org.h2.jdbc.JdbcSQLException: Cannot parse "TIMESTAMP" constant "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"; SQL statement:

[SQL statement]

at org.h2.util.DateTimeUtils.parseDateValue(DateTimeUtils.java:275)
at org.h2.value.ValueTimestamp.parseTry(ValueTimestamp.java:140)
at org.h2.value.ValueTimestamp.parse(ValueTimestamp.java:120)
at org.h2.value.Value.convertTo(Value.java:862)
at org.h2.table.Column.convert(Column.java:148)
at org.h2.command.dml.Insert.insertRows(Insert.java:143)
at org.h2.command.dml.Insert.update(Insert.java:114)
at org.h2.command.CommandContainer.update(CommandContainer.java:78)
at org.h2.command.Command.executeUpdate(Command.java:254)
at org.h2.jdbc.JdbcPreparedStatement.execute(JdbcPreparedStatement.java:198)
at org.skife.jdbi.v2.SQLStatement.internalExecute(SQLStatement.java:1328)
at org.skife.jdbi.v2.Update.execute(Update.java:56)
at org.skife.jdbi.v2.sqlobject.UpdateHandler$2.value(UpdateHandler.java:62)
at org.skife.jdbi.v2.sqlobject.UpdateHandler.invoke(UpdateHandler.java:75)
at org.skife.jdbi.v2.sqlobject.SqlObject.invoke(SqlObject.java:175)
at org.skife.jdbi.v2.sqlobject.SqlObject$1.intercept(SqlObject.java:75)
at org.skife.jdbi.v2.sqlobject.CloseInternalDoNotUseThisClass$$EnhancerByCGLIB$$4df23516.insert(<generated>)
4

1 回答 1

3

我们可以通过将参数工厂注册到 DBI 来做到这一点。

public class DateTimeArgumentFactory implements ArgumentFactory<DateTime> {
    @Override
    public boolean accepts(Class<?> expectedType, Object value, StatementContext ctx) {
        return value != null && DateTime.class.isAssignableFrom(value.getClass());
    }

    @Override
    public Argument build(Class<?> expectedType, final DateTime value, StatementContext ctx) {
        return new Argument() {
            @Override
            public void apply(int position, PreparedStatement statement, StatementContext ctx) throws SQLException {
                statement.setTimestamp(position, new java.sql.Timestamp(value.getMillis()));
            }
        };
    }
}

通过以下方式将此参数工厂注册到 DBI，

  dbi.registerArgumentFactory(new DateTimeArgumentFactory());

这将自动将 DateTime 转换为 sql TimeStamp。

于 2015-06-06T06:00:50.967 回答