嗨,我想为我的本地 opencpu 开发服务器提供一个简单的功能。
getLinearInterpolatedEstimateQuantil <- function(x, type, probs){
result = quantile(data, type, probs)
result #print for simpler debug
}
示例调试输入将类似于
{"type":1,"x":[1,2,3,4,5,6,7,8,9,10],"probs":[0.05,0.25,0.75,0.95]}
但是有一个问题:当手动提供样本数据时,例如:
debugInput = fromJSON(file("debugInput.json"))
代码编译。
但是当我尝试通过 http 访问它时:
opencpu$browse("library/myLibrary")
curl http://localhost:3469/ocpu/library/predictR/R/getLinearInterpolatedEstimateQuantil/Json -d '{"type":1,"x":[1,2,3,4,5,6,7,8,9,10],"probs":[0.05,0.25,0.75,0.95]}
' -H "内容类型:应用程序/json"
我只收到输出:
unused arguments (type = 1, probs = probs)
In call:
getLinearInterpolatedEstimateQuantil(type = 1L, x = x, probs = probs)
所以我希望解析与数组有一些问题?
我希望你能告诉我我的代码有什么问题。
编辑:我了解到 opencpu 为我执行 json 解析。但是代码仍然不起作用。(https://www.opencpu.org/posts/scoring-engine/)编辑:仍然无法正常工作编辑:奇怪:调用本机函数有效:
curl http://localhost:5112/ocpu/library/stats/R/quantile/json -d '{"type":1,"x":[1,2,3,4,5,6,7,8,9,10],"probs":[0.05,0.25,0.75,0.95]}' -H "Content-Type: application/json"
但是调用我自己的函数会导致错误:
curl http://localhost:5112/ocpu/library/predictR/R/getLinearInterpolatedEstimateQuantil/json -d '{"type":1,"x":[1,2,3,4,5,6,7,8,9,10],"probs":[0.05,0.25,0.75,0.95]}' -H "Content-Type: application/json"
unused arguments (type = 1, probs = probs)
In call:
getLinearInterpolatedEstimateQuantil(type = 1L, x = x, probs = probs)
再次澄清我的功能:
getLinearInterpolatedEstimateQuantil <- function(x){
result = quantile(data, type, probs)
return (result)
}
再次编辑:
library(jsonlite)
myFunction <- function(x, type, probs){
result = quantile(x, type, probs)
return (result)
}
json <- '{"type":1,"x":[1,2,3,4,5,6,7,8,9,10],"probs":[0.05,0.25,0.75,0.95]}'
args <- fromJSON(json)
do.call(myFunction, args)
结果是
100%
10
Warning message:
In if (na.rm) x <- x[!is.na(x)] else if (anyNA(x)) stop("missing values and NaN's not allowed if 'na.rm' is FALSE") :
Bedingung hat Länge > 1 und nur das erste Element wird benutzt
和
do.call(stats::quantile, args)
结果是
5% 25% 75% 95%
1 3 8 10
为什么第一次调用会导致输出不同的警告?为什么第二个电话有效?