2

出于某种原因，当我在最后运行代码时，它只是显示消息而不加密或解密它我真的很困惑如果这真的很明显，请不要讨厌我我对python很陌生，几乎不知道基础知识

#declare variables
NewWord =""
NewLetter = ""
SecretMessage = 0

mode = input("Please enter a mode: ").lower()  #makes it lowercase
message = input("Please enter a message: ").lower() # lowercase to tackle capitals
while True:
    try:
        offset = int(input("Please enter a number: ")) #If no exception occurs, the except clause is skipped and execution of the try statement is finished.
        break
    except ValueError: #If exception occurs, the except clause continues printing not a valid number and letting you re-enter the offset and not just throwing up an error.
        print ("Not a valid number")
#print(mode, message, offset) #Test to check user Input

for letter in message : 
    SecretMessage = ord(letter)
    if mode == "Encrypt" :
        SecretMessage += offset # add the offset to the letter
    if mode == "Decrypt" :
         SecretMessage -= offset # subtract the offset to the letter
    if SecretMessage < 97:
       SecretMessage  += 26
    if SecretMessage > 122:
        SecretMessage -= 26
    NewLetter = SecretMessage 
    NewLetter = chr(NewLetter) 

   # print(newLetter)# check conversion
    NewWord += NewLetter

print(NewWord)
4

2 回答 2

0 
mode = input("Please enter a mode: ").lower()

使模式全部小写，以防止它等于“加密”或“解密”。所以，你的if条款没有被执行。

于 2015-05-29T13:09:37.733 回答
0

你正在小写mode变量，所以它不可能等于Encryptor Decrypt。您必须测试这些单词的小写版本：

if mode == "encrypt" :
    SecretMessage += offset # add the offset to the letter
if mode == "decrypt" :
     SecretMessage -= offset # subtract the offset to the letter
于 2015-05-29T13:10:50.757 回答