这是我目前的情况:
- 我有两个 tm 结构,都设置为当前时间
- 我在其中一个结构中更改了小时
- 这种变化神奇地发生在另一个结构中......
- 如何防止这种情况发生?我需要能够比较并知道两个不同时间之间的秒数——当前时间和未来时间。我一直在使用 difftime 和 mktime 来确定这一点。我认识到我在技术上不需要两个 tm 结构(另一个结构可能只是加载了原始时间的 time_t),但我仍然有兴趣了解为什么会发生这种情况。
无效跟踪器::监视器(字符*缓冲区){
// time handling
time_t systemtime, scheduletime, currenttime;
struct tm * dispatchtime;
struct tm * uiuctime;
double remainingtime;
// let's get two structs operating with current time
dispatchtime = dispatchtime_tm();
uiuctime = uiuctime_tm();
// set the scheduled parameters
dispatchtime->tm_hour = 5;
dispatchtime->tm_min = 05;
dispatchtime->tm_sec = 14;
uiuctime->tm_hour = 0;
// both of these will now print the same time! (0:05:14)
// what's linking them??
// print the scheduled time
printf ("Current Time : %2d:%02d:%02d\n", uiuctime->tm_hour, uiuctime->tm_min, uiuctime->tm_sec);
printf ("Scheduled Time : %2d:%02d:%02d\n", dispatchtime->tm_hour, dispatchtime->tm_min, dispatchtime->tm_sec);
}
struct tm* Tracker::uiuctime_tm(){
time_t uiucTime;
struct tm *ts_uiuc;
// give currentTime the current time
time(&uiucTime);
// change the time zone to UIUC
putenv("TZ=CST6CDT");
tzset();
// get the localtime for the tz selected
ts_uiuc = localtime(&uiucTime);
// set back the current timezone
unsetenv("TZ");
tzset();
// set back our results
return ts_uiuc;
}
struct tm* Tracker::dispatchtime_tm(){
time_t currentTime;
struct tm *ts_dispatch;
// give currentTime the current time
time(¤tTime);
// get the localtime for the tz selected
ts_dispatch = localtime(¤tTime);
// set back our results
return ts_dispatch;
}