我想用 VHDL 制作一个 4 位加法器和减法器,我创建了 1 位全加器、异或门(用于减法)和一个 4 位加法器,如下所示:
全加器:
LIBRARY ieee;
USE ieee.std_logic_1164.all;
ENTITY FullAdder_1_Bit IS
PORT(
X, Y : IN STD_LOGIC;
CIn : IN STD_LOGIC;
Sum : OUT STD_LOGIC;
COut : OUT STD_LOGIC
);
END FullAdder_1_Bit;
ARCHITECTURE Behavier OF FullAdder_1_Bit IS
BEGIN
Sum <= X XOR Y XOR CIn;
COut <= (X AND Y) OR (X AND CIn) OR (Y AND CIn);
END Behavier;
异或门:
LIBRARY ieee;
USE ieee.std_logic_1164.all;
ENTITY XORGate IS
PORT(
X1, X2 : IN STD_LOGIC;
Y : OUT STD_LOGIC
);
END XORGate;
ARCHITECTURE Declare OF XORGate IS
BEGIN
Y <= X1 XOR X2;
END Declare;
4位加法器:
LIBRARY ieee;
USE ieee.std_logic_1164.all;
ENTITY Adder_4_Bit IS
PORT(
A, B : IN STD_LOGIC_VECTOR(3 DOWNTO 0);
Mode : IN STD_LOGIC;
Sum : OUT STD_LOGIC_VECTOR(3 DOWNTO 0);
COut : OUT STD_LOGIC
);
END Adder_4_Bit;
ARCHITECTURE Structure OF Adder_4_Bit IS
COMPONENT FullAdder_1_Bit IS
PORT(
X, Y : IN STD_LOGIC;
CIn : IN STD_LOGIC;
Sum : OUT STD_LOGIC;
COut : OUT STD_LOGIC
);
END COMPONENT;
COMPONENT XORGate IS
PORT(
X1, X2 : IN STD_LOGIC;
Y : OUT STD_LOGIC
);
END COMPONENT;
SIGNAL COut_Temp : STD_LOGIC_VECTOR(2 DOWNTO 0);
SIGNAL XB : STD_LOGIC_VECTOR(3 DOWNTO 0);
BEGIN
B_0 : XORGate PORT MAP(Mode, B(0), XB(0));
B_1 : XORGate PORT MAP(Mode, B(1), XB(1));
B_2 : XORGate PORT MAP(Mode, B(2), XB(2));
B_3 : XORGate PORT MAP(Mode, B(3), XB(3));
SUM_0 : FullAdder_1_Bit
PORT MAP (A(0), XB(0), Mode, Sum(0), COut_Temp(0));
SUM_1 : FullAdder_1_Bit
PORT MAP (A(1), XB(1), COut_Temp(0), Sum(1), COut_Temp(1));
SUM_2 : FullAdder_1_Bit
PORT MAP (A(2), XB(2), COut_Temp(1), Sum(2), COut_Temp(2));
SUM_3 : FullAdder_1_Bit
PORT MAP (A(3), XB(3), COut_Temp(2), Sum(3), COut);
END;
在我的主要代码中,我使用了那些(比如测试台!):
LIBRARY ieee;
USE ieee.std_logic_1164.all;
USE ieee.std_logic_unsigned.ALL;
ENTITY Add_AND_Sub IS
END Add_AND_Sub;
ARCHITECTURE Declare OF Add_AND_Sub IS
COMPONENT Adder_4_Bit IS
PORT(
A, B : IN STD_LOGIC_VECTOR(3 DOWNTO 0);
Mode : IN STD_LOGIC;
Sum : OUT STD_LOGIC_VECTOR(3 DOWNTO 0);
COut : OUT STD_LOGIC
);
END COMPONENT;
SIGNAL A, B : STD_LOGIC_VECTOR(4 DOWNTO 0);
SIGNAL Mode : STD_LOGIC;
SIGNAL As, Bs, E, AVF : STD_LOGIC;
SIGNAL XA, XB, Sum : STD_LOGIC_VECTOR(3 DOWNTO 0);
BEGIN
Add : Adder_4_Bit
PORT MAP(XA, XB, Mode, Sum, E);
PROCESS(A, B, Mode)
BEGIN
As <= A(4);
Bs <= B(4);
XA <= A(3 DOWNTO 0);
XB <= B(3 DOWNTO 0);
CASE Mode IS
WHEN '0' =>
IF ((As XOR Bs) = '1') THEN
Mode <= '1';
XA <= Sum;
AVF <= '0';
IF (E = '1') THEN
IF (XA = "0000") THEN
As <= '0';
END IF;
ELSE
XA <= (NOT XA) + "0001";
As <= NOT As;
END IF;
ELSE
XA <= Sum;
END IF;
WHEN '1' =>
IF ((As XOR Bs) = '1') THEN
Mode <= '0';
XA <= Sum;
AVF <= E;
ELSE
AVF <= '0';
XA <= Sum;
IF (E = '1') THEN
IF (XA = "0000") THEN
As <= '0';
END IF;
ELSE
XA <= (NOT XA) + "0001";
As <= NOT As;
END IF;
END IF;
WHEN Others =>
--
END CASE;
END PROCESS;
END Declare;
主要场景是对该算法进行建模:
但现在我想在 XA 和 As 中输出
- 我应该使用算法中显示的寄存器,例如“E”和“AVF”
有一个问题:
我们知道端口映射是连续连接的,所以当我改变模式值时,结果(总和)必须改变,是真的吗?!
我已经尝试过这段代码,但我无法在 XA 中获得输出,并且总和值没有 True 结果,我知道我的主代码(进程)中存在一些问题,但我找不到问题
请检查该代码并告诉我出了什么问题!
编辑:
我使用 ModelSim 及其模拟来测试我的代码,首先我强制“A”、“B”和“模式”的值然后运行以获得结果和波形
谢谢 ...