我正在尝试从 torrent 文件中提取大小和名称，并使用 bencode 解码 torrent 文件的内容。
我做了pip install bencode然后我用一个种子文件的一行进行了测试，你可以在那里看到。
import bencode
blabla = 'd8:announce70:http://tracker.t411.io:56969/c5faa6720249d33ff6ba2af48640af89/announce7:comment29:https://www.t411.io/t/524280210:created by19:https://www.t411.io13:creation datei1431685353e4:infod6:lengthi14634059e4:name22:Charlie-Hebdo-1178.pdf12:piece lengthi262144e6:pieces1120:'
myprint = bencode.decode_string(blabla,1)
print myprint
这是 pip install 放在 python 库中的文件：
from BTL import BTFailure
def decode_int(x, f):
f += 1
newf = x.index('e', f)
n = int(x[f:newf])
if x[f] == '-':
if x[f + 1] == '0':
raise ValueError
elif x[f] == '0' and newf != f+1:
raise ValueError
return (n, newf+1)
def decode_string(x, f):
colon = x.index(':', f)
n = int(x[f:colon])
if x[f] == '0' and colon != f+1:
raise ValueError
colon += 1
return (x[colon:colon+n], colon+n)
def decode_list(x, f):
r, f = [], f+1
while x[f] != 'e':
v, f = decode_func[x[f]](x, f)
r.append(v)
return (r, f + 1)
def decode_dict(x, f):
r, f = {}, f+1
while x[f] != 'e':
k, f = decode_string(x, f)
r[k], f = decode_func[x[f]](x, f)
return (r, f + 1)
decode_func = {}
decode_func['l'] = decode_list
decode_func['d'] = decode_dict
decode_func['i'] = decode_int
decode_func['0'] = decode_string
decode_func['1'] = decode_string
decode_func['2'] = decode_string
decode_func['3'] = decode_string
decode_func['4'] = decode_string
decode_func['5'] = decode_string
decode_func['6'] = decode_string
decode_func['7'] = decode_string
decode_func['8'] = decode_string
decode_func['9'] = decode_string
def bdecode(x):
try:
r, l = decode_func[x[0]](x, 0)
except (IndexError, KeyError, ValueError):
raise BTFailure("not a valid bencoded string")
if l != len(x):
raise BTFailure("invalid bencoded value (data after valid prefix)")
return r
from types import StringType, IntType, LongType, DictType, ListType, TupleType
class Bencached(object):
__slots__ = ['bencoded']
def __init__(self, s):
self.bencoded = s
def encode_bencached(x,r):
r.append(x.bencoded)
def encode_int(x, r):
r.extend(('i', str(x), 'e'))
def encode_bool(x, r):
if x:
encode_int(1, r)
else:
encode_int(0, r)
def encode_string(x, r):
r.extend((str(len(x)), ':', x))
def encode_list(x, r):
r.append('l')
for i in x:
encode_func[type(i)](i, r)
r.append('e')
def encode_dict(x,r):
r.append('d')
ilist = x.items()
ilist.sort()
for k, v in ilist:
r.extend((str(len(k)), ':', k))
encode_func[type(v)](v, r)
r.append('e')
encode_func = {}
encode_func[Bencached] = encode_bencached
encode_func[IntType] = encode_int
encode_func[LongType] = encode_int
encode_func[StringType] = encode_string
encode_func[ListType] = encode_list
encode_func[TupleType] = encode_list
encode_func[DictType] = encode_dict
try:
from types import BooleanType
encode_func[BooleanType] = encode_bool
except ImportError:
pass
def bencode(x):
r = []
encode_func[type(x)](x, r)
return ''.join(r)
事实是我真的不明白如何用这个 bencode 解码我的线路。
我已经尝试过 defbdecode但这是输出：
root@debian:/home/florian/Téléchargements# python decript.py
Traceback (most recent call last):
File "decript.py", line 4, in <module>
myprint = bencode.bdecode(blabla)
File "/usr/local/lib/python2.7/dist-packages/bencode/__init__.py", line 68, in bdecode
raise BTFailure("not a valid bencoded string")
bencode.BTL.BTFailure: not a valid bencoded string
所以我尝试使用 defdecode_string但decode_string(blabla, 1)它只解码第一个单词：
root@debian:/home/florian/Téléchargements# python decript.py
('announce', 11)
并且像 2、3、4 这样的数字不起作用并显示如下错误：
root@debian:/home/florian/Téléchargements# python decript.py
Traceback (most recent call last):
File "decript.py", line 4, in <module>
myprint = bencode.decode_string(blabla,10)
File "/usr/local/lib/python2.7/dist-packages/bencode/__init__.py", line 29, in decode_string
n = int(x[f:colon])
ValueError: invalid literal for int() with base 10: 'e70'
我想解码所有行，但我不明白如何使用这个 bencode 来做到这一点。