5

是否可以一次使用 Dagger 2.0 构造函数注入和单例。我在文档中找不到答案。

例子:

@Singleton
public class MyClass {
   private final OtherClass member;

   @Inject
   public MyClass(OtherClass member){
        this.member = member;
   }
 }

构造函数注入确实有效。但是,如果我在班级上写@Singleton,是否可以保证 MyClass 被创建为单例?

谢谢

4

1 回答 1

11

是的。

由于 Dagger 2 为您生成源代码,因此很容易检查正在发生的事情。例如,将以下模块与您的 结合使用时MyClass

@Component
@Singleton
public interface MyComponent {
  MyClass myClass();
}

生成以下实现:

@Generated("dagger.internal.codegen.ComponentProcessor")
public final class DaggerMyComponent implements MyComponent {
  private Provider<MyClass> myClassProvider;

  private DaggerMyComponent(Builder builder) {  
    assert builder != null;
    initialize(builder);
  }

  public static Builder builder() {  
    return new Builder();
  }

  public static MyComponent create() {  
    return builder().build();
  }

  private void initialize(final Builder builder) {  
    this.myClassProvider = ScopedProvider.create(MyClass_Factory.create(OtherClass_Factory.create()));
  }

  @Override
  public MyClass myClass() {  
    return myClassProvider.get();
  }

  public static final class Builder {
    private Builder() {  
    }

    public MyComponent build() {  
      return new DaggerMyComponent(this);
    }
  }
}

initialize(Builder)中,您可以看到 aScopedProvider被用作Providerfor MyClass。调用myClass()方法时,会调用ScopedProvider'sget()方法,实现为单例:

public T get() {
  // double-check idiom from EJ2: Item 71
  Object result = instance;
  if (result == UNINITIALIZED) {
    synchronized (this) {
      result = instance;
      if (result == UNINITIALIZED) {
        instance = result = factory.get();
      }
    }
  }
  return (T) result;
}
于 2015-05-20T21:25:14.980 回答