4

我遇到了无法修复的内存泄漏。我使用 MemoryAnalizer 确定了它发生的位置，但我徒劳地努力摆脱它。这是代码：

public class MyActivity extends Activity implements SurfaceHolder.Callback {
 ...

Camera.PictureCallback mPictureCallbackJpeg = new Camera.PictureCallback() {
    public void onPictureTaken(byte[] data, Camera c) {
        try  {
            // log the action
            Log.e(getClass().getSimpleName(), "PICTURE CALLBACK JPEG: data.length = " + data);

            // Show the ProgressDialog on this thread 
            pd = ProgressDialog.show(MyActivity.this, "", "Préparation", true, false); 

            // Start a new thread that will manage the capture 
            new ManageCaptureTask().execute(data, c); 
        }
        catch(Exception e){
            AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this);
            ...
            dialog.create().show();
        }
    }

    class ManageCaptureTask extends AsyncTask<Object, Void, Boolean> { 
        protected Boolean doInBackground(Object... args) {
            Boolean isSuccess = false;

            // initialize the bitmap before the capture
            ((myApp) getApplication()).setBitmapX(null);
            try{

                // Check if it is a real device or an emulator
                TelephonyManager telmgr = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
                String deviceID = telmgr.getDeviceId();
                boolean isEmulator = "000000000000000".equalsIgnoreCase(deviceID);

                // get the bitmap
                if (isEmulator) {
                    ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeFile(imageFileName));
                } else {
                    ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length));
                }

                ((myApp) getApplication()).setImageForDB(ImageTools.resizeBmp(((myApp) getApplication()).getBmp()));
                // convert the bitmap into a grayscale image and display it in the preview
                ((myApp) getApplication()).setImage(makeGrayScale());
                isSuccess = true;
            }
            catch (Exception connEx){
                errorMessageFromBkgndThread = getString(R.string.errcapture);
            }
            return isSuccess; 
        } 

        protected void onPostExecute(Boolean result) { 
            // Pass the result data back to the main activity 
            if (MyActivity.this.pd != null) { 
                MyActivity.this.pd.dismiss(); 
            } 
            if (result){
                ((ImageView) findViewById(R.id.apercu)).setImageBitmap(((myApp) getApplication()).getBmp());    
                ((myApp) getApplication()).setBitmapX(null);
            }
            else{
                // there was an error
                ErrAlert();
            }
        } 
    }     
};
private void ErrAlert(){
    // notify the user about the error
    AlertDialog.Builder dialog = new AlertDialog.Builder(this);
    ...
    dialog.create().show();
}

}

活动在单击按钮时终止，如下所示：

Button use = (Button) findViewById(R.id.use);
use.setOnClickListener(new OnClickListener() {
    @Override
    public void onClick(View v) {
        Intent intent = new Intent(MyActivity.this, NextActivity.class);
        intent.putExtra("dbID", "-1");
        intent.putExtra("category", category);
        ((myApp) getApplication()).setBitmapX(null);
        MyActivity.this.startActivity(intent);
        MyActivity.this.finish();
        }
    });

MemoryAnalyzer 在以下位置指示内存泄漏：

((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length));

我很感激任何建议，提前谢谢你。

4

2 回答 2

10

你的线程垃圾是在 onPostExecute 被调用之后收集的还是还在内存中？

关闭活动时，不会取消或销毁异步任务。如果您的线程或多或少是轻量级的并且在一小段时间后完成，请保持它运行并添加一个 MyActivity.this。onPostExecute() 方法中的isFinishing()子句。

您的 Task 存储对您的 Activity MyActivity.this 的隐式引用，因为它是 Activity 内部的私有类。这意味着在任务退出之前，您的 Activity 不会被垃圾收集。

于 2010-06-14T09:16:47.307 回答
0

你可以试试下面的代码片段

protected void onPostExecute(Boolean result) {
    if(YourActivity.this.isFinished()){
        //to smomething here
    }
}
于 2017-08-25T06:53:36.660 回答