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我想使用刚刚获得的授权码为我的应用程序获取访问令牌。我正在使用此代码

DefaultHttpClient client = new DefaultHttpClient();
URI uri = new URIBuilder().setScheme("https")
        .setHost("www.linkedin.com")
        .setPath("/uas/oauth2/accessToken")
        .setParameter("grant_type", "authorization_code")
        .setParameter("code", code)
        .setParameter("redirect_uri", "http://localhost:9090/ConnectSocialMedia/callBack.jsp")
        .setParameter("client_id", CONSUMER_KEY_OPTION)
        .setParameter("client_secret", CONSUMER_SECRET_OPTION)
        .build();
HttpPost post = new HttpPost(uri);
post.setHeader("Content-Type", "application/x-www-form-urlencoded");
HttpResponse response2 = client.execute(post);
System.out.println("Final Response------------>"+response2);

但我收到HTTP/1.1 400 Bad Request。我究竟做错了什么?

任何帮助将非常感激!

4

1 回答 1

1

您将参数作为 URL 中的查询参数添加到令牌端点,但它们应该在 POST 参数中传递。你应该使用类似的东西:

DefaultHttpClient client = new DefaultHttpClient();
URI uri = new URIBuilder().setScheme("https")
    .setHost("www.linkedin.com")
    .setPath("/uas/oauth2/accessToken")
    .build();

List <NameValuePair> nvps = new ArrayList <NameValuePair>();
nvps.add(new BasicNameValuePair("grant_type", "authorization_code"));
nvps.add(new BasicNameValuePair("code", code));
nvps.add(new BasicNameValuePair("redirect_uri", "http://localhost:9090/ConnectSocialMedia/callBack.jsp"));
nvps.add(new BasicNameValuePair("client_id", CONSUMER_KEY_OPTION));
nvps.add(new BasicNameValuePair("client_secret", CONSUMER_SECRET_OPTION));

HttpPost post = new HttpPost(uri);
post.setEntity(new UrlEncodedFormEntity(nvps));
HttpResponse response2 = client.execute(post);
System.out.println("Final Response------------>"+response2);
于 2015-05-18T08:47:30.517 回答