1

我正在构建一个页面，用户可以在其中对 Colander 和 Deform 中的任意数量的产品进行评论。我已经掌握了所有必需的元素，但我仍然有一些连接点的问题。具体来说，我如何强制（动态地）创建 N 个表单项的序列，然后为它们绑定数据？

这是我到目前为止的尝试：

reviews =[
        {
            "product": "Shampoo",
            "comment": ""
            "rating": 3,
        },

        {
            "product": "Soap",
            "comment": "",
            "rating:" 3,
        },
    ]

rating = colander.Schema()
rating.add(colander.SchemaNode(colander.Int(), name="rating", missing=colander.null, validator=colander.Range(1, 5)))
rating.add(colander.SchemaNode(colander.String(), name="comment", validator=colander.Length(max=4096), missing=""))
ratings = colander.SequenceSchema(name="ratings", default=reviews, children=[rating])

# schema.add(colander.SchemaNode(colander.Sequence(), rating, name="ratings", default=reviews))
schema = CSRFSchema()
schema.add(ratings)

form = deform.Form(schema)
if request.method == "POST":
    controls = request.POST.items()

    try:
        captured = form.validate(controls)
    except deform.ValidationFailure as e:
        return {'form': e.render()}
else:
    rendered_form = form.render()

return locals()

但这会导致错误：

ValueError: Prototype for <deform.field.Field object at 4576735072 (schemanode 'ratings')> has no name
4

1 回答 1

1

好的 - 想通了。最里面的SchemaNode()必须命名。必须使用colander.SchemaNode(colander.Sequence())来绘制项目序列。

reviews =[
        {
            "product": "Shampoo",
            "comment": "",
            "rating": 3,
        },

        {
            "product": "Soap",
            "comment": "",
            "rating": 3,
        },
    ]

rating = colander.Schema(name="single_rating")
rating.add(colander.SchemaNode(colander.Int(), name="rating", missing=colander.null, validator=colander.Range(1, 5)))
rating.add(colander.SchemaNode(colander.String(), name="comment", validator=colander.Length(max=4096), missing=""))
ratings = colander.SchemaNode(colander.Sequence(), rating, name="ratings", default=reviews)

# schema.add(colander.SchemaNode(colander.Sequence(), rating, name="ratings", default=reviews))
schema = CSRFSchema()
schema.add(ratings)

form = deform.Form(schema)
if request.method == "POST":
    controls = request.POST.items()

    try:
        captured = form.validate(controls)
    except deform.ValidationFailure as e:
        return {'form': e.render()}
else:
    rendered_form = form.render()

return locals()
于 2015-05-17T23:27:00.790 回答