3

我写了这个 Django ORM 查询：

queryset = Test.objects.all() \
    .annotate_test_date() \ # similar to extract hour 
    .annotate_test_time() \ # similar to extract hour 
    .annotate(hour=Extract(F('created_on'), function='hour')) \
    .annotate(count=Count('id')) \
    .order_by() \
    .values('hour', 'count')

形成的查询结果是：

SELECT extract (hour from ("users_test"."created_on")) AS "hour",
COUNT("users_test"."id") AS "count" 
FROM "users_test" 
GROUP BY "users_test"."id", "users_test"."author_id", "users_test"."created_on", "users_test"."modified_on", "users_test"."access_point_id", "users_test"."user_id", "users_test"."invite_id", "users_test"."building_id", "users_test"."company_id", date("users_test"."created_on"), "time"("users_test"."created_on"), extract (hour from ("users_test"."created_on"))

但所需的查询是：

SELECT extract (hour from ("users_test"."created_on")) AS "hour",
COUNT("users_test"."id") AS "count" 
FROM "users_test" 
GROUP BY extract (hour from ("users_test"."created_on"))

我相信这是由于我的查询中有额外的注释字段，但这些字段是过滤所必需的。

任何帮助表示赞赏。

提前致谢

4

1 回答 1

0

按此顺序尝试：

queryset = Test.objects.all() \
    .annotate(hour=Extract(F('created_on'), function='hour')) \
    .annotate(count=Count('id')) \
    .values('hour', 'count')
    .order_by()
于 2015-05-17T13:45:05.227 回答