37

我试图弄清楚如何将我的路线拆分成单独的文件。

到目前为止我有这个，但它不起作用。我只是Not found在尝试访问时得到http://localhost:3001/api/things

//server.js
var koa = require('koa');
var app = koa();
var router = require('koa-router');

app.use(router(app));
require('./routes')(app);


// routes.js
module.exports = function *(app){
  app.use('/api/things', require('./api/things'));
};


// api/things/index.js

var Router = require('koa-router');
var router = new Router({
  prefix: '/api/things'
});

router.get('/', function *(){
  this.body = [{ name: 'Foo'}, { name: 'Bar' }];
});

module.exports = router;
4

8 回答 8

74

编辑：我更新了下面的代码示例，因为koa-router不再维护 npm 上的包。Koa 团队以@koa/router.

对于任何阅读本文，对如何在 Koa 2.X 中执行此操作感到好奇的人：

应用程序.js

import Koa from 'koa'
import rootRouter from './routes/root'
import userRouter from './routes/user'

const app = new Koa()

app.use(rootRouter.routes())
app.use(rootRouter.allowedMethods())
app.use(userRouter.routes())
app.use(userRouter.allowedMethods())

export default app

路线/root.js

import Router from '@koa/router'
const router = new Router()

router.get('/', async (ctx, next) => {
  ctx.body = 'Hello'
})

export default router

路线/user.js

import Router from '@koa/router'
const router = new Router({ prefix: '/user' })

router.get('/', async (ctx, next) => {
  ctx.body = 'Some User'
})

export default router

如果您想避免与routes()和的重复allowedMethods()，您可以使用koa-compose将中间件组合在一起。为简单起见，我围绕它做了一个包装以简化使用koa-router. 使用它看起来像这样：

应用程序.js

import Koa from 'koa'
import router from './routes'

const app = new Koa()

app.use(router())

export default app

路线/index.js

import combineRouters from 'koa-combine-routers'
import rootRouter from './root'
import userRouter from './user'

const router = combineRouters(
  rootRouter,
  userRouter
)

export default router

它也会做同样的事情。

于 2016-09-02T23:51:22.153 回答
19

服务器.js

var app = require('koa')();
var router = require('./routes');
app.use(router.routes());
app.use(router.allowedMethods());
app.listen(3000);

路由.js

var router = require('koa-router')();
router.get('/', function* () {
    this.body = 'router test';
});
module.exports = router;
于 2015-05-20T09:34:45.920 回答
12

像这样的东西应该工作：

// app.js
var koa = require('koa'),
    app = koa();

require('./routes1')(app);
require('./routes2')(app);

app.listen(3000);

// routes1.js
var Router = require('koa-router');
function register (app) {
  var router = new Router({
    prefix: '/api'
  });
  router.get('/', ...); // responds to "/api"
  router.get('/messages', ...); // responds to "/api/messages"
  app.use(router.routes());
  app.use(router.allowedMethods());
}

module.exports = register

// routes2.js
var Router = require('koa-router');
function register (app) {
  var router = new Router();
  router.get('/', ...); // responds to "/"
  app.use(router.routes());
  app.use(router.allowedMethods());
}

module.exports = register
于 2015-05-18T13:54:15.267 回答
7

对于 Koa 2.x，我找到了带有前缀的嵌套路由来交付货物，没有额外的包裹。

假设/api/dogs和/api/cats是必需的结果。

像这样：

应用程序.js

import Koa from 'koa';
import Router from 'koa-router';
import apiRouter from './routes/apiRouter';

const app = new Koa();

app.use(apiRouter.routes(), apiRouter.allowedMethods());

app.listen(3000);

export default app;

路线/apiRouter.js

import Router from 'koa-router'

import dogsRouter from './dogsRouter'
import catsRouter from './catsRouter'

const apiRouter = new Router({ prefix: '/api' })

const nestedRoutes = [dogsRouter, catsRouter]
for (var router of nestedRoutes) {
    apiRouter.use(router.routes(), router.allowedMethods())
}

export default apiRouter;

路线/dogsRouter.js

import Router from 'koa-router'

const dogsRouter = new Router({ prefix: '/dogs' });

dogsRouter.get('/', async (ctx, next) => {
  ctx.body = 'Dogs be here'
});

export default dogsRouter;

路线/catsRou​​ter.js

import Router from 'koa-router'

const catsRouter = new Router({ prefix: '/cats' });

catsRouter.get('/', async (ctx, next) => {
  ctx.body = 'Cats be here'
});

export default catsRouter;
于 2019-02-13T09:56:07.133 回答
4

我认为TJ在做的时候会牢记在心的简约方法

koa, koa-route, koa-mount

使用以您喜欢的方式安装的小型独立应用程序的方法：

index.js

var app = require('./app')
app.listen(3000);

应用程序.js

const Koa = require('koa')
const _ = require('koa-route')
const mount = require('koa-mount')
const app = new Koa()
const pets = require('./pets')

// sub apps
app.use(mount('/pets', pets))

// root app
app.use(_.get('/', function(){
  this.body = "hello";
}))

module.exports = app;

宠物.js

var Koa = require('koa');
var _ = require('koa-route');
var app = new Koa();


app.use(_.get('/', ctx => ctx.body = "pets" ));
app.use(_.get('/:name', (ctx, name) => ctx.body = "pet: "+ name));

module.exports = app;
于 2016-11-03T10:58:25.290 回答
3

这是我最终的结果：

//server.js
'use strict';

var koa = require('koa');
var app = koa();
var serve = require('koa-static');
var path = require('path');
var router = require('koa-router');
var cfg = require('./config');
var mw = require('./middleware');

app.use(serve(path.resolve(__dirname, '../client')));
app.use(mw.requestTime('Response-time'));
app.use(router(app));
app.use(cfg.db.connect);

require('./routes')(app);

app.get('/api', function *(){
  this.body = 'Welcome to API v1';
});

app.use(cfg.db.close);
app.listen(cfg.env.port);



//routes.js
module.exports = function (app){
  app.use(require('./api/things').routes());
};


// api/things/index.js
var Router = require('koa-router');

var router = new Router({
  prefix: '/api/things'
});

var ctrl = require('./controllers');

router.get('/', ctrl.list);
router.get('/:id', ctrl.get);
router.post('/', ctrl.post);
router.put('/:id', ctrl.put);
router.del('/:id', ctrl.del);

module.exports = router;


// api/things/controllers.js

var r = require('rethinkdb');
var http = require('http');
var parse = require('co-body');
var ctrl = module.exports = {};

ctrl.list = function *(next){
};

ctrl.get = function *(next){
};

ctrl.post = function *(next){
};

ctrl.put = function *(next){
};

ctrl.del = function *(next){
};
于 2015-05-18T21:53:34.143 回答
2

您可以将所有路由放在一个名为 routes 的文件夹中，然后遍历该文件夹中的所有文件，请求它们并初始化。这样，对于任何新路线，只需在路线文件夹中创建一个文件即可。

所以是这样的：

index.js

const Koa = require("koa");
const logger = require("koa-logger");
const bodyParser = require("koa-bodyparser");

const app = new Koa();

app.use(logger());
app.use(bodyParser());

require("./routes")(app);

const server = app.listen(config.server.port);

module.exports = server;

/routes/index.js

const fs = require("fs");
const path = require("path");
const baseName = path.basename(module.filename);

const routes = fs
    .readdirSync(path.join(__dirname))
    .filter(
        file =>
            file.indexOf(".") !== 0 &&
            file !== baseName &&
            file.slice(-3) === ".js"
    )
    .map(file => require(path.join(__dirname, file)));

module.exports = function(app) {
    for (var router of routes) {
        app.use(router.routes());
    }
};

然后在您想要的 /routes 文件夹中

/routes/user.js

/routes/customer.js

这些都是路由器出口，例如

/routes/auth.js

const Router = require("koa-router");
const authControllers = require("../controllers/auth");

const {
    jwtAuth,
    login,
    register,
    forgotPassword,
    resetPassword,
    getAuthenticatedUser
} = authControllers;

const router = new Router({ prefix: "/auth" });

router.post("/register", register);
router.post("/login", login);
router.post("/forgot-password", forgotPassword);
router.post("/reset-password/:resetToken", resetPassword);
router.get("/profile", jwtAuth, getAuthenticatedUser);

module.exports = router;
于 2020-01-29T10:35:12.600 回答
0

类似，但正是我需要的是：

应用程序.js

"use strict";
import Koa from 'koa';
const app = new Koa();

import Router from 'koa-router';
const router = new Router();

import mount from 'koa-mount';
import routes from "./router/index.mjs";

app.use(mount(routes));
app.use(router.routes());

app.listen(3000, () => console.log("Listening on port: 3000"));

路由器/index.mjs

"use strict";
import Koa from 'koa';
const app = new Koa();

import Router from 'koa-router';
const router = new Router();

router.get('/', async (ctx, next) => {
    ctx.body = {success: true};
    await next();
});

app.use(router.routes());

export default app;

于 2021-05-28T07:19:52.783 回答