我从一位经验丰富的程序员那里拿了这个问题来准备编程测试。
问题：
给定购买金额和作为付款的金额，计算作为找零返回的每种货币面额的数量和类型。总是先用最高面额的钱找零。使用的纸币面额为 100 美元、50 美元、20 美元、10 美元、5 美元和 1 美元。硬币的面额为 0.25 美元、0.10 美元、0.05 美元和 0.01 美元。
INPUT：将有 5 行输入。每行将包含 2 个有理数，分别代表购买金额和支付金额。
输出：对于每个输入行，使用使用的非零面额的数量按从高到低的大小顺序打印变化。如果没有更改到期打印 NONE。示例输出 #1 表示：1-$5、2-$1、1-$.25、2-$.10 和 2-$.01。
采样输入 采样输出
1. 12.53, 20.00 1. 121221
2. 11.33, 15.00 2. 32112
3. 35.64, 50.00 3. 14111
4. 72.67, 100.00 4. 112113 2102
5. 106.13 23102, 106.13, 5. 106.13
我决定创建两个程序：一个长的、更容易理解的程序和一个精简的版本。
这是长篇：
import java.util.*;
public class Prac13CorrectChange {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
for (int A = 1; A <= 5; A++) {
System.out
.println("What is the amount of your purchase and the amount given as your payment?");
String input = in.nextLine();
String[] data = input.split(",");
double $amount = Double.parseDouble(data[0]);
double price = Double.parseDouble(data[1]);
double change = price - $amount;
int ans1 = ((int) (change / 100));
change = change - (ans1 * 100);
int ans2 = ((int) (change / 50));
change = change - (ans2 * 50);
int ans3 = ((int) (change / 20));
change = change - (ans3 * 20);
int ans4 = ((int) (change / 10));
change = change - (ans4 * 10);
int ans5 = ((int) (change / 5));
change = change - (ans5 * 5);
int ans6 = ((int) (change / 1));
change = change - (ans6 * 1);
int ans7 = ((int) (change / .25));
change = change - (ans7 * .25);
int ans8 = ((int) (change / .10));
change = change - (ans8 * .10);
int ans9 = ((int) (change / .05));
change = change - (ans9 * .05);
int ans10 = ((int) (change / .01));
change = change - (ans10 * .01);
String answer = "";
if (ans1 != 0) {
answer = answer + Integer.toString(ans1);
}
if (ans2 != 0) {
answer = answer + Integer.toString(ans2);
}
if (ans3 != 0) {
answer = answer + Integer.toString(ans3);
}
if (ans4 != 0) {
answer = answer + Integer.toString(ans4);
}
if (ans5 != 0) {
answer = answer + Integer.toString(ans5);
}
if (ans6 != 0) {
answer = answer + Integer.toString(ans6);
}
if (ans7 != 0) {
answer = answer + Integer.toString(ans7);
}
if (ans8 != 0) {
answer = answer + Integer.toString(ans8);
}
if (ans9 != 0) {
answer = answer + Integer.toString(ans9);
}
if (ans10 != 0) {
answer = answer + Integer.toString(ans10);
}
System.out.println(answer);
}
}
}
这是精简版。
import java.util.Scanner;
public class Prac15CorrectChangeShort {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
for (int A = 1; A <= 5; A++) {
System.out
.println("What is the amount of your purchase and the amount given as your payment?");
String input = in.nextLine();
String[] data = input.split(",");
double $amount = Double.parseDouble(data[0]);
double price = Double.parseDouble(data[1]);
double change = price - $amount;
int ans[] = new int[10];
double money[] = { 100, 50, 20, 10, 5, 1, 0.25, 0.10, 0.05, 0.01 };
for (int looptimes = 0; looptimes < 10; looptimes++) {
ans[looptimes] = ((int) (change / money[looptimes]));
change = change - (ans[looptimes] * money[looptimes]);
}
for (int looptimes = 0; looptimes < 10; looptimes++) {
if (ans[looptimes] != 0) {
System.out.print(ans[looptimes]);
}
}
System.out.print('\n');
}
}
}
我遇到的主要问题是，无论我进行什么调试，它都会给我错误的输出 #2-5。最后一位数字少了1。给我这个问题的程序员和我都找不到发生这种情况的任何原因。
请帮忙。