3

考虑这个非常简单的程序:

#include <boost/type_erasure/is_placeholder.hpp>
#include <boost/iterator/iterator_adaptor.hpp>

int main()
{
    return 0;
}

这无法编译:

  include/boost/type_erasure/is_placeholder.hpp:31:33: error: reference to 'use_default' is ambiguous
    struct is_placeholder< ::boost::use_default> : ::boost::mpl::false_ {};
                                    ^
    include/boost/iterator/iterator_adaptor.hpp:44:18: note: candidate found by name lookup is 'boost::use_default'
    using iterators::use_default;
                     ^
    include/boost/type_erasure/is_placeholder.hpp:21:8: note: candidate found by name lookup is 'boost::use_default'
    struct use_default;
           ^
    1 error generated.

我不想去更改那些头文件。我该如何解决这个问题?

4

1 回答 1

1

A temporary solution would be replace

struct use_default;

in `boost/type_erasure/is_placeholder.hpp' with

namespace iterators {
    struct use_default;
}
using iterators::use_default;

Which is found in `boost/iterator/iterator_adaptor.hpp'.

于 2015-09-01T01:50:18.517 回答