我正在尝试在 MySQL 中完成以下操作（请参阅pseudo代码）
SELECT DISTINCT gid
FROM `gd`
WHERE COUNT(*) > 10
ORDER BY lastupdated DESC
有没有办法在 WHERE 子句中不使用 (SELECT...) 来做到这一点，因为这似乎是一种资源浪费。
Ice
问问题
325378 次
9 回答
307
尝试这个;
select gid
from `gd`
group by gid
having count(*) > 10
order by lastupdated desc
于 2008-11-19T12:52:53.303 回答
30
我不确定你想要做什么......也许像
SELECT gid, COUNT(*) AS num FROM gd GROUP BY gid HAVING num > 10 ORDER BY lastupdated DESC
于 2008-11-19T12:52:55.470 回答
20
SELECT COUNT(*)
FROM `gd`
GROUP BY gid
HAVING COUNT(gid) > 10
ORDER BY lastupdated DESC;
编辑（如果你只想要gids）：
SELECT MIN(gid)
FROM `gd`
GROUP BY gid
HAVING COUNT(gid) > 10
ORDER BY lastupdated DESC
于 2008-11-19T12:52:12.197 回答
17
只是没有条款的学术版本：
select *
from (
select gid, count(*) as tmpcount from gd group by gid
) as tmp
where tmpcount > 10;
于 2013-09-10T12:25:29.150 回答
15
尝试
SELECT DISTINCT gid
FROM `gd`
group by gid
having count(*) > 10
ORDER BY max(lastupdated) DESC
于 2008-11-19T12:52:59.963 回答
15
WHERE 子句中不能有聚合函数（例如 COUNT、MAX 等）。因此，我们改用 HAVING 子句。因此，整个查询将与此类似：
SELECT column_name, aggregate_function(column_name)
FROM table_name
WHERE column_name operator value
GROUP BY column_name
HAVING aggregate_function(column_name) operator value;
于 2016-01-20T09:11:21.507 回答
7
COUNT(*) 只能与 HAVING 一起使用，并且必须在 GROUP BY 语句之后使用 请看以下示例：
SELECT COUNT(*), M_Director.PID FROM Movie
INNER JOIN M_Director ON Movie.MID = M_Director.MID
GROUP BY M_Director.PID
HAVING COUNT(*) > 10
ORDER BY COUNT(*) ASC
于 2019-09-05T13:45:20.733 回答
6
-- 搜索缺少半小时记录的气象站
SELECT stationid
FROM weather_data
WHERE `Timestamp` LIKE '2011-11-15 %' AND
stationid IN (SELECT `ID` FROM `weather_stations`)
GROUP BY stationid
HAVING COUNT(*) != 48;
-- yapiskan 的变体，带有 where .. in .. select
于 2011-11-16T13:22:00.343 回答
1
我认为你不能添加count()with where。现在看看为什么....
where不一样having，having意味着你正在工作或处理小组和计数相同的工作，它也在处理整个小组，
现在如何计算它作为一个整体工作
创建一个表并输入一些ID，然后使用：
select count(*) from table_name
您会发现总值意味着它表示某个组！where添加count();也是如此
于 2012-04-05T06:32:27.480 回答