事实上MyClass x = 120;
,是否可以创建这样一个自定义类?如果是这样,我该怎么做?
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4 回答
5
It's generally considered a bad idea to use implicit operators, as they are, after all, implicit and run behind your back. Debugging code littered with operator overloads is a nightmare. That said, with something like this:
public class Complex
{
public int Real { get; set; }
public int Imaginary { get; set; }
public static implicit operator Complex(int value)
{
Complex x = new Complex();
x.Real = value;
return x;
}
}
you could use:
Complex complex = 10;
or you could ever overload the + operator
public static Complex operator +(Complex cmp, int value)
{
Complex x = new Complex();
x.Real = cmp.Real + value;
x.Imaginary = cmp.Imaginary;
return x;
}
and use code like
complex +=5;
于 2010-06-10T15:01:32.030 回答
3
不确定这是否是您想要的,但您可以通过实现隐式运算符来实现:http: //msdn.microsoft.com/en-us/library/z5z9kes2 (VS.71).aspx
于 2010-06-10T14:52:14.647 回答
3
创建一个隐式运算符:
http://msdn.microsoft.com/en-us/library/z5z9kes2.aspx
例如:
public struct MyStruct // I assume this is what you meant, since you mention struct in your title, but use MyClass in your example.
{
public MyClass(int i) { val = i; }
public int val;
// ...other members
// User-defined conversion from MyStruct to double
public static implicit operator int(MyStruct i)
{
return i.val;
}
// User-defined conversion from double to Digit
public static implicit operator MyStruct(int i)
{
return new MyStruct(i);
}
}
“这是一个好主意吗?” 值得商榷。隐式转换往往会破坏程序员公认的标准;通常不是一个好主意。但是,例如,如果您正在做一些大型价值库,那么这可能是一个好主意。
于 2010-06-10T14:52:47.167 回答
0
是的,这是一个简短的例子......
public struct MyCustomInteger
{
private int val;
private bool isDef;
public bool HasValue { get { return isDef; } }
public int Value { return val; } }
private MyCustomInteger() { }
private MyCustomInteger(int intVal)
{ val = intVal; isDef = true; }
public static MyCustomInteger Make(int intVal)
{ return new MyCustomInteger(intVal); }
public static NullInt = new MyCustomInteger();
public static explicit operator int (MyCustomInteger val)
{ if (!HasValue) throw new ArgumentNullEception();
return Value; }
public static implicit operator MyCustomInteger (int val)
{ return new MyCustomInteger(val); }
}
于 2010-06-10T14:58:23.247 回答