如何使用 C# 遍历文件夹结构而不陷入连接点的陷阱?
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2264 次
2 回答
9
对于那些不知道的人:连接点的行为类似于 linux 上文件夹的符号链接。当您设置递归文件夹结构时,会发生提到的陷阱,如下所示:
given folder /a/b
let /a/b/c point to /a
then
/a/b/c/b/c/b becomes valid folder locations.
我建议像这样的策略。在 Windows 上,您被限制为路径字符串的最大长度,因此递归解决方案可能不会破坏堆栈。
private void FindFilesRec(
string newRootFolder,
Predicate<FileInfo> fileMustBeProcessedP,
Action<FileInfo> processFile)
{
var rootDir = new DirectoryInfo(newRootFolder);
foreach (var file in from f in rootDir.GetFiles()
where fileMustBeProcessedP(f)
select f)
{
processFile(file);
}
foreach (var dir in from d in rootDir.GetDirectories()
where (d.Attributes & FileAttributes.ReparsePoint) != FileAttributes.ReparsePoint
select d)
{
FindFilesRec(
dir.FullName,
fileMustBeProcessedP,
processFile);
}
}
于 2008-11-19T09:37:00.903 回答
-2
您可以使用以下代码:
private void processing(string directory)
{
cmbFilesTypesSelectedIndex = cmbFilesTypes.SelectedIndex;
CheckForProjectFile(directory);
DirectoryInfo dInfo = new DirectoryInfo(directory);
DirectoryInfo[] dirs = dInfo.GetDirectories() ;
foreach (DirectoryInfo subDir in dirs)
{
CheckForProjectFile(subDir.FullName);
processing(subDir.FullName);
}
}
private void CheckForProjectFile(string directory)
{
Boolean flag = false;
DirectoryInfo dirInfo = new DirectoryInfo(directory);
FileInfo[] files = dirInfo.GetFiles();
//You can also traverse in files also
foreach (FileInfo subfile in files)
{
//Do you want
}
}
于 2008-11-19T09:45:28.283 回答