1

在定义与 Symfony 1.4 的一对多关系时,我得到了意想不到的行为(对我来说!)。这是一个演示行为的简单示例,有一个 Employer 表和一个 Employee 表:一个 Employer 可以有多个 Employees。YML 模式文件如下:

Employee:
  columns:
    id: { type: integer, primary: true, autoincrement: true }
    first_name: { type: string(30), notnull: true }
    last_name: { type: string(30), notnull: true }
    employer_id: { type: integer }
  relations:
    Employer:
      local: employer_id
      foreign: id
      type: one
      foreignType: many
      foreignAlias: Workers

Employer:
  columns:
    id: { type: integer, primary: true, autoincrement: true }
    name: { type: string(100) }
    line1: { type: string(100) }
    city: { type: string(100) }
    state: { type: string(10) }

因此,调用getWorkers()雇主应返回与雇主相关联的雇员。getWorkers()第一次被调用时,我得到了这种预期的行为。

但是,在随后的调用中,如果已经向雇主添加了额外的员工(以编程方式或直接在 DB [MySQL] 中),getWorkers()调用仍会返回第一个结果。

我已经通过单步执行调用的 Symfony 源来验证getWorkers(),在随后的调用中,它会返回存储在_references数组中的缓存值。

如果我以编程方式遵循外键,Employee通过查询employee_id,那么我会得到完整的结果集。

谁能解释这种行为?

这是我在“动作”中运行的一些示例 PHP 代码,它演示了该行为:

// Create common employer.
$employer = new Employer();
$employer->setName("My Employer");
$employer->setLine1("100 Main Street");
$employer->setCity("AnyTown");
$employer->setState("State");
$employer->save();

// Create two employees,
$worker1 = new Employee();
$worker1->setFirstName("John");
$worker1->setLastName("Doe");
$worker1->setEmployer($employer);
$worker1->save();

$worker2 = new Employee();
$worker2->setFirstName("Jane");
$worker2->setLastName("Smith");
$worker2->setEmployer($employer);
$worker2->save();

$myEmployer = Doctrine_Core::getTable('Employer')->findOneBy('name', 'My Employer');
$workers = $myEmployer->getWorkers();
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This gives the expected 2 employees.

// Now create another employee in the common employer.
$worker3 = new Employee();
$worker3->setFirstName("Anne");
$worker3->setLastName("Droid");
$worker3->setEmployer($employer);
$worker3->save();

$myEmployer = Doctrine_Core::getTable('Employer')->findOneBy('name', 'My Employer');
$workers = $myEmployer->getWorkers();
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This still gives 2 employees, whereas there are 3 in the DB.

// Follow FK directly.
$workers = Doctrine_Core::getTable('Employee')->findBy('employer_id', $myEmployer->getId());
echo "Number of workers for " . $myEmployer->getName() . ' is ' . count($workers);
// This gives the expected 3 employees.

我如何强制它每次都重新关注这种关系?

4

1 回答 1

2

添加新的相关记录时,您可能需要刷新记录的关系。

您可以执行以下任一操作:

$worker->refresh(true);
$worker->refreshRelated();
$worker->refreshRelated('Employer');

有关更多信息,您应该查看: Doctrine Documentation - Refreshing Relationships

于 2010-06-10T20:16:59.197 回答