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我即将使用 mandrill 和 djrill 1.3.0 和 django 1.7 将一些批量电子邮件功能集成到一个项目中，因为我正在发送 html 内容，所以我使用以下方法：

from django.core.mail import get_connection

connection = get_connection()
to = ['testaddress1@example.com', 'testaddress1@example.com'] 
for recipient_email in to:
    # I perform some controls and register some info about the user and email address
    subject = u"Test subject for %s" % recipient_email
    text = u"Test text for email body"
    html = u"<p>Test text for email body</p>"
    from_email = settings.DEFAULT_FROM_EMAIL
    msg = EmailMultiAlternatives(
        subject, text, from_email, [recipient_email])
    msg.attach_alternative(html, 'text/html')
    messages.append(msg)
# Bulk send
send_result = connection.send_messages(messages)

此时，send_result是一个 int，它等于发送（推送到 mandrill）消息的数量。

我需要为每条发送的消息获取 mandrill 响应以处理 mandrill_response['msg']['_id'] 值和其他一些东西。

djrill 提供的 'send_messages' 连接方法使用 _send 调用，它将 mandrill_response 添加到每条消息，但如果成功则返回 True。

那么，您知道在使用 djrill 发送批量 html 电子邮件时如何获得 mandrill 响应吗？

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1 回答 1

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Djrill 在mandrill_response发送每个 EmailMessage 对象时为其附加一个属性。请参阅Djrill 文档中的Mandrill 响应。

messages因此，在您发送消息后，您可以检查您发送的列表中每个对象的该属性。就像是：

# Bulk send
send_result = connection.send_messages(messages)

for msg in messages:
   if msg.mandrill_response is None:
       print "error sending to %r" % msg.to
   else:
       # there's one response for each recipient of the msg
       # (because an individual message can have multiple to=[..., ...])
       for response in msg.mandrill_response:
           print "Message _id %s, to %s, status %s" % (
               response['_id'], response['email'], response['status'])

>>> Message _id abc123abc123abc123abc123abc123, to testaddress1@example.com, status sent
>>> ...
于 2015-05-06T18:35:16.360 回答