0

我的注册 AsyncTask 工作正常,我的数据保存在 PHP MYSQL 上工作良好,但我面临一个异常。

 public class SignupJson extends AsyncTask<String,String,String> {


            //SignupJSONParser sjson = new SignupJSONParser();
            JSONObject json = new JSONObject();
            //private static final String TAG_SUCCESS = "success";

            HttpParams mhttpparams = new BasicHttpParams();


            @Override
            protected void onPreExecute() {

                pDialog = new ProgressDialog(SignupActivity.this);
                pDialog.setMessage("Creating Account..");
                pDialog.setIndeterminate(false);
                pDialog.setCancelable(true);
                pDialog.show();
                super.onPreExecute();
            }

            @Override
            protected String doInBackground(String... args) {

                String getName = _Name.getText().toString();
                String  getEmail = _Email.getText().toString();
                String  getPassword = _Password.getText().toString();

         List<NameValuePair> pair = new    ArrayList<NameValuePair>();
                pair.add(new BasicNameValuePair("name",getName));
                pair.add(new BasicNameValuePair("id",getEmail));
                pair.add(new BasicNameValuePair("pass", getPassword));

                // int success=0;
                json = JSONParser.makeHttpRequest( URL,"POST", pair);

                Log.d("Create Response", json.toString());

                try {

                    String success = json.getString(TAG_SUCCESS);

                    //success = json.getInt(TAG_SUCCESS);

                    if (json.getString(TAG_SUCCESS)!=null) {

                        if (Integer.parseInt(success)==1)
                        {


                        Log.d("User Created!", json.toString());
                        Intent login = new Intent(getApplicationContext(), LoginActivity.class);
                        startActivity(login);
                        // closing this screen

                        finish();

                        //return json.getString(TAG_MESSAGE);

                    }
                        else {

                            Log.d("Registration Failure!", json.getString(TAG_MESSAGE));

                            return json.getString(TAG_MESSAGE);
                        }
                    }

                } catch (JSONException e) {
                    e.printStackTrace();
                    // success=0;
                }

                return null;
                // return ""+success;
            }

            @Override
            protected void onPostExecute(String s) {


                pDialog.dismiss();

                if (json != null){
                    Toast.makeText(getApplicationContext(),"Registration Done",Toast.LENGTH_SHORT).show();
                    //Toast.makeText(MainActivity.this, json.toString(), Toast.LENGTH_LONG).show();
                }

            }



        }

    }

日志猫:

com.example.ahmadkhan.routeapp W/System.err: org.json.JSONException: No value for success /com.example.ahmadkhan.routeapp W/System.err: at org.json.JSONObject.get(JSONObject.java: 354)com.example.ahmadkhan.routeapp W/System.err:在 org.json.JSONObject.getString(JSONObject.java:514) /com.example.ahmadkhan.routeapp W/System.err:在 com.example.ahmadkhan .routeapp.SignupActivity$SignupJson.doInBackground(SignupActivity.java:169) com.example.ahmadkhan.routeapp W/System.err﹕在 com.example.ahmadkhan.routeapp.SignupActivity$SignupJson.doInBackground(SignupActivity.java:129) com .example.ahmadkhan.routeapp W/System.err:在 android.os.AsyncTask$2.call(AsyncTask.java:287) com.example.ahmadkhan.routeapp W/System.err:在 java.util.concurrent.FutureTask。运行(FutureTask.java:234)com.example。ahmadkhan.routeapp W/System.err:在 android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230) com.example.ahmadkhan.routeapp W/System.err:在 java.util.concurrent.ThreadPoolExecutor.runWorker (ThreadPoolExecutor.java:108com.example.ahmadkhan.routeapp W/System.err﹕在 java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:57com.example.ahmadkhan.routeapp W/System.err﹕在 java .lang.Thread.run(Thread.java:841)错误:在 java.lang.Thread.run(Thread.java:841)错误:在 java.lang.Thread.run(Thread.java:841)

在线错误

String success = json.getString(TAG_SUCCESS);

//success = json.getInt(TAG_SUCCESS);

if (json.getString(TAG_SUCCESS)!=null) {
}

任何人都可以建议我一个解决方案如何摆脱这个错误,并告诉我如何在与 PHP Wamp Server 连接成功和失败的情况下处理服务器响应。

4

3 回答 3

1
org.json.JSONException: No value for success
//means no key-value found for this key - "success"

使用 has() 方法处理此异常

if(<jsonobject>.has("success"))
{
   //your code
}
于 2015-05-05T09:09:11.080 回答
0

JSONObject.get*()当在对象中找不到输入键时,方法不会返回,它们会抛出.nullJSONException

例如getString()

抛出: JSONException - 如果键没有字符串值。

使用JSONObject.opt*()方法,而不是:

String success = json.optString(TAG_SUCCESS);
if (success != null) {
    // ...
}
于 2015-05-05T08:57:38.213 回答
0

试试这个我希望它会帮助你..!

JSONObject json = JSONParser.makeHttpRequest( URL,"POST", pair);

           if(json!=null)
             {
            Log.d("Create Response", json.toString());

            try {

                String success = json.getString(TAG_SUCCESS);

                //success = json.getInt(TAG_SUCCESS);

                if (json.getString(TAG_SUCCESS)!=null) {

                    if (Integer.parseInt(success)==1)
                    {


                    Log.d("User Created!", json.toString());
                    Intent login = new Intent(getApplicationContext(),  LoginActivity.class);
                    startActivity(login);
                    // closing this screen

                    finish();

                    //return json.getString(TAG_MESSAGE);

                }
                    else {

                        Log.d("Registration Failure!", json.getString(TAG_MESSAGE));

                        return json.getString(TAG_MESSAGE);
                    }
                }

            } catch (JSONException e) {
                e.printStackTrace();
                // success=0;
            }
      }else{
          Log.d("getting null response from server!");
       }
于 2015-05-05T09:27:07.460 回答