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我正在尝试使用 RestSharp 包装 Plivo API（是的，我知道它已经完成）。

但是，我找不到将 API 命名约定转换为我自己的方法，例如：

“呼叫”（https://www.plivo.com/docs/api/call/#make-an-outbound-call）至少需要：

to, from, 和answer_url参数被提供。

这些参数也区分大小写。

我希望能够提供一个 CallRequest 类，以我喜欢的命名约定包装所需的数据，然后在 RestSharp 序列化之前以某种方式翻译这些数据。

例子：

public class CallRequest
{

    /// <summary>
    /// The phone number to be used as the caller id (with the country code).For e.g, a USA caller id number could be, 15677654321, with '1' for the country code.
    /// </summary>
    public string From { get; set; }

    /// <summary>
    ///  The regular number(s) or sip endpoint(s) to call. Regular number must be prefixed with country code but without the + sign). For e.g, to dial a number in the USA, the number could be, 15677654321, with '1' for the country code. Multiple numbers can be sent by using a delimiter. For e.g. 15677654321<12077657621<12047657621. Sip endpoints must be prefixed with sip: E.g., sip:john1234@phone.plivo.com. To make bulk calls, the delimiter < is used. For eg. 15677654321<15673464321<sip:john1234@phone.plivo.com Yes, you can mix regular numbers and sip endpoints.
    /// </summary>
    public string To { get; set; }

    /// <summary>
    /// The URL invoked by Plivo when the outbound call is answered.
    /// </summary>
    public string AnswerUrl { get; set; }

}

然后，这些数据将在以下函数中转换为 Plivo 的约定：

    private T Execute<T>(IRestRequest request) where T : new()
    {
        var client = new RestClient
        {
            BaseUrl = new Uri(BaseUrl),
            Authenticator = new HttpBasicAuthenticator(_accountId, _authToken),
            UserAgent = "PlivoSharp"
        };
        request.AddHeader("Content-Type", "application/json");
        request.AddParameter("auth_id", _accountId, ParameterType.UrlSegment);
        request.RequestFormat = DataFormat.Json;
        client.AddHandler("application/json", new JsonDeserializer());


        var response = client.Execute<T>(request);
        if (response.ErrorException == null) return response.Data;
        const string message = "Error retrieving response.  Check inner details for more info.";
        var plivoException = new ApplicationException(message, response.ErrorException);
        throw plivoException;
    }

    public CallResponse MakeCall(CallRequest callRequest)
    {
        var request = new RestRequest
        {
            RequestFormat = DataFormat.Json,
            Resource = "Account/{auth_id}/Call/",
            Method = Method.POST
        };

        //SOMEHOW TRANSLATE THE PROPERTIES INTO THE DATA BELOW 

        request.AddBody(new
        {
            to = "17#####",
            from = "18#####",
            answer_url = "http://m------.xml"
        });

        return Execute<CallResponse>(request);
    }
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1 回答 1

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不幸的是，看起来 JSON 属性重命名并没有在 RestSharp 中开箱即用地实现。你有几个选择：

  1. 从https://github.com/restsharp/RestSharp下载 Restsharp并自己重建它，启用编译器选项SIMPLE_JSON_DATACONTRACT。然后，您将能够使用数据协定属性重命名属性。有关更多信息，请参见此处：RestSharp JsonDeserializer with special characters in identifiers

    我刚刚在启用此选项的情况下重建了最新版本的 RestSharp（版本 105.1.0）。使用以下版本的课程：

    [DataContract]
public class CallRequest
{
    [DataMember(Name = "from")]
    public string From { get; set; }

    [DataMember(Name = "to")]
    public string To { get; set; }

    [DataMember(Name = "answer_url")]
    public string AnswerUrl { get; set; }
}

    我能够生成以下 JSON：

        var request = new CallRequest { AnswerUrl = "AnswerUrl", From = "from", To = "to" };
    var json = SimpleJson.SerializeObject(request);
    Debug.WriteLine(json);
    // Prints {"from":"from","to":"to","answer_url":"AnswerUrl"}

    但是，我不确定这个选项的测试有多彻底，因为它是默认编译出来的。

  2. 使用支持属性重命名的 Json.NET 等不同的序列化程序手动进行序列化和反序列化。为此，请参阅RestSharp - 使用 Json.net 序列化程序（在此处存档。）

于 2015-05-04T20:48:40.823 回答