2

给定一个 url 和一个查询字符串，我怎样才能得到查询字符串与 url 组合产生的 url？

我正在寻找类似于 .htaccess 的功能qsa。我意识到完全手动实现这将是相当微不足道的，但是是否有处理查询字符串的内置函数可以简化或完全解决这个问题？

示例输入/结果集：

Url="http://www.example.com/index.php/page?a=1"
QS ="?b=2"
Result="http://www.example.com/index.php/page?a=1&b=2"

-

Url="page.php"
QS ="?b=2"
Result="page.php?b=2"
4

5 回答 5

8

不使用 PECL 扩展并且不是大量复制和粘贴函数的东西怎么样？它仍然有点复杂，因为您将两个查询字符串拼接在一起，并且希望以一种不仅仅是$old .= $new;

我们将使用parse_url从所需的 url 中提取查询字符串，使用parse_str解析您希望连接的查询字符串，使用array_merge将它们连接在一起，并使用http_build_query为我们创建新的组合字符串。

// Parse the URL into components
$url = 'http://...';
$url_parsed = parse_url($url);
$new_qs_parsed = array();
// Grab our first query string
parse_str($url_parsed['query'], $new_qs_parsed);
// Here's the other query string
$other_query_string = 'that=this&those=these';
$other_qs_parsed = array();
parse_str($other_query_string, $other_qs_parsed);
// Stitch the two query strings together
$final_query_string_array = array_merge($new_qs_parsed, $other_qs_parsed);
$final_query_string = http_build_query($final_query_string_array);
// Now, our final URL:
$new_url = $url_parsed['scheme'] 
         . '://'
         . $url_parsed['host'] 
         . $url_parsed['path'] 
         . '?'      
         . $final_query_string;
于 2010-06-09T01:12:43.033 回答
1

您可以使用以下方法从 url 获取查询字符串部分：

$_SERVER['QUERY_STRING']

然后将其正常附加到url。

如果要在查询字符串中指定自己的自定义变量，请查看：

http_build_query

于 2010-06-09T00:44:48.237 回答
0

这是从 WordPress“框架”中获取的一系列功能，可以做到这一点，但这很可能太多了：

add_query_arg()

/**
 * Retrieve a modified URL query string.
 *
 * You can rebuild the URL and append a new query variable to the URL query by
 * using this function. You can also retrieve the full URL with query data.
 *
 * Adding a single key & value or an associative array. Setting a key value to
 * emptystring removes the key. Omitting oldquery_or_uri uses the $_SERVER
 * value.
 *
 * @since 1.0
 *
 * @param mixed $param1 Either newkey or an associative_array
 * @param mixed $param2 Either newvalue or oldquery or uri
 * @param mixed $param3 Optional. Old query or uri
 * @return string New URL query string.
 */
public function add_query_arg() {
    $ret = '';
    if ( is_array( func_get_arg(0) ) ) {
        $uri = ( @func_num_args() < 2 || false === @func_get_arg( 1 ) ) ? $_SERVER['REQUEST_URI'] : @func_get_arg( 1 );
    } else {
        $uri = ( @func_num_args() < 3 || false === @func_get_arg( 2 ) ) ? $_SERVER['REQUEST_URI'] : @func_get_arg( 2 );
    }

    if ( $frag = strstr( $uri, '#' ) ) {
        $uri = substr( $uri, 0, -strlen( $frag ) );
    } else {
        $frag = '';
    }

    if ( preg_match( '|^https?://|i', $uri, $matches ) ) {
        $protocol = $matches[0];
        $uri = substr( $uri, strlen( $protocol ) );
    } else {
        $protocol = '';
    }

    if ( strpos( $uri, '?' ) !== false ) {
        $parts = explode( '?', $uri, 2 );
        if ( 1 == count( $parts ) ) {
            $base = '?';
            $query = $parts[0];
        } else {
            $base = $parts[0] . '?';
            $query = $parts[1];
        }
    } elseif ( !empty( $protocol ) || strpos( $uri, '=' ) === false ) {
        $base = $uri . '?';
        $query = '';
    } else {
        $base = '';
        $query = $uri;
    }

    parse_str( $query, $qs );

    if ( get_magic_quotes_gpc() )
        $qs = format::stripslashes_deep( $qs );

    $qs = format::urlencode_deep( $qs ); // this re-URL-encodes things that were already in the query string
    if ( is_array( func_get_arg( 0 ) ) ) {
        $kayvees = func_get_arg( 0 );
        $qs = array_merge( $qs, $kayvees );
    } else {
        $qs[func_get_arg( 0 )] = func_get_arg( 1 );
    }

    foreach ( ( array ) $qs as $k => $v ) {
        if ( $v === false )
            unset( $qs[$k] );
    }

    $ret = http_build_query( $qs, '', '&' );
    $ret = trim( $ret, '?' );
    $ret = preg_replace( '#=(&|$)#', '$1', $ret );
    $ret = $protocol . $base . $ret . $frag;
    $ret = rtrim( $ret, '?' );
    return $ret;
}

stripslashes_deep()

/**
 * Navigates through an array and removes slashes from the values.
 *
 * If an array is passed, the array_map() function causes a callback to pass the
 * value back to the function. The slashes from this value will removed.
 *
 * @since 1.0
 *
 * @param array|string $value The array or string to be stripped
 * @return array|string Stripped array (or string in the callback).
 */
function stripslashes_deep( $value ) {
    return is_array( $value ) ? array_map( array('self', 'stripslashes_deep'), $value ) : stripslashes( $value );
}

urlencode_deep()

/**
 * Navigates through an array and encodes the values to be used in a URL.
 *
 * Uses a callback to pass the value of the array back to the function as a
 * string.
 *
 * @since 1.0
 *
 * @param array|string $value The array or string to be encoded.
 * @return array|string $value The encoded array (or string from the callback).
 */
public function urlencode_deep( $value ) {
    return is_array($value) ? array_map( array('self', 'urlencode_deep'), $value) : urlencode($value);
}
于 2010-06-09T00:47:49.643 回答
0

没有内置函数可以做到这一点。但是，您可以从 http PECL 扩展中使用此功能，

http://usphp.com/manual/en/function.http-build-url.php

例如，

$url = http_build_url("http://www.example.com/index.php/page?a=1",
    array(
        "b" => "2"
    )
);
于 2010-06-09T00:51:17.500 回答
0

那么如果url冲突怎么办？如果两个 url 都b=在查询字符串中包含一个组件？你需要决定哪个占主导地位。

这是一段代码，可以满足您的要求，将每个字符串解析为 url，然后提取queryurl 部分并将implode()它们重新组合在一起。

$url="http://www.example.com/index.php/page?a=1";
$qs ="?b=2";

$url_parsed = parse_url($url);
$qs_parsed = parse_url($qs);

$args = array(
    $url_parsed['query'],
    $qs_parsed['query'],
);

$new_url = $url_parsed['scheme'];
$new_url .= '://';
$new_url .= $url_parsed['host'];
$new_url .= $url_parsed['path'];
$new_url .= '?';
$new_url .= implode('&', $args);

print $new_url;
于 2010-06-09T01:29:49.873 回答