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我有这个 json 数据

{"data": [{"id": 3,"nameAr": "Test","nameEn": "Test","active": 1,
"subCategories": [{"id": 27,"nameAr": "Test",
"nameEn": "Test","active": 0,
"sections": [{"id": 53,"nameAr": "Test",
"nameEn": "Test","active": 0},
{"id": 52,"nameAr": "Test","nameEn": "Test","active": 0
}]}]}],"code": "1001","message": "success"
}

在使用 JSONModel https://github.com/icanzilb/JSONModel解析这个 json 时

解析这个的代码

self.categoriesModels = [CategoryModel arrayOfModelsFromDictionaries: [results objectForKey:@"data"]];

并尝试访问嵌套的 json

categoryModel.subCategories

我收到了这个错误

-[CategoryModel subCategories]：无法识别的选择器发送到实例 0x17404b910 2015-05-03 20:38:15.019 AkshefFeen[2268:786267] * 由于未捕获的异常“NSInvalidArgumentException”而终止应用程序，原因：'-[CategoryModel subCategories]：无法识别的选择器sent to instance 0x17404b910' * First throw call stack: (0x185fb42d8 0x1977800e4 0x185fbb3a4 0x185fb8154 0x185ebaccc 0x100027608 0x18ab1d474 0x18abd7790 0x18aa78240 0x18a9e86ec 0x185f6c2a4 0x185f69230 0x185f69610 0x185e952d4 0x18f6b36fc 0x18aa5afac 0x10002d220 0x197dfea08) libc++abi.dylib: terminating with uncaught exception of type NSException

我的模特

1 - CategoryModel.h

#import "JSONModel.h"
#import "SubCategoryModel.h"

@protocol CategoryModel
@end

@interface CategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SubCategoryModel>* subCategories;

@end

2 - SubCategoryModel.h

@protocol SubCategoryModel
@end

@interface SubCategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SectionModel,Optional>* subCategories;

@end

3 - SectionModel.h

#import "JSONModel.h"

@protocol SectionModel
@end

@interface SectionModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;

@end

为什么我会收到此错误，以及如何解决？

4

1 回答 1

1

@ahmed Shoeib：可能有 2 个可能的原因：1. 可能是因为您的任何 JSONModel 类中的 @synthesize 关键字。

  1. 这可能是由于父对象和子对象之间的命名相同。

请参阅此链接以了解 JSONModel 中的首选命名约定：单击此处

或者您可以在这里提出相同的问题，您将获得官方答案或解决方案：点击这里

于 2015-08-11T13:35:41.820 回答