关于系统:
- 系统共有 8 个表 - Users - Tutor_Details(Tutors 是 User 的一种,Tutor_Details 表链接到 Users) - learning_packs,(存储由导师创建的包) - learning_packs_tag_relations,(保存用于搜索的标签关系) - utors_tag_relations 和标签和订单(包含导师包的购买细节),order_details 链接到订单和tutor_details。
要更清楚地了解所涉及的表格,请查看最后的表格部分。
- 正在遵循基于标签的搜索方法。当新导师注册和导师创建包时创建标签关系(这使得导师和包可搜索)。有关详细信息,请查看标签如何在此系统中工作?以下。
以下是我试图优化的更复杂查询的更简单表示(不是实际的):-我使用explanation of parts
了查询中的语句
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select
SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches,
SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches,
td.*, u.*, count(distinct(od.id_od)), `if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity`
from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user
LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor
LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp
LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including
Learning_Packs table)`
LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on
od.id_order = o.id_order
LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor
JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag)
where `some condition on Users table's fields`
AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp > 0)) THEN `some
conditions on learning pack tables set` ELSE 1 END
AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc > 0)) THEN `some
conditions on webclasses tables set` ELSE 1 END
AND CASE WHEN (od.id_od>0) THEN od.id_author = td.id_tutor and `some conditions on Orders table's fields` ELSE 1 END
AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%")
group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1
order by tutor_popularity desc, u.surname asc, u.name asc limit
0,20
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上面的查询是做什么的?
- 是否对搜索关键字进行 AND 逻辑搜索(本例中为 2 - “民主”和“独裁”)。
- 仅返回两个关键字都存在于两个集合中的那些导师 - 导师详细信息和导师创建的所有包的详细信息。
为了清楚起见 - 假设一个名为“Sandeepan Nath”的导师创建了一个包“我的第一个包”,那么:-
- 搜索“Sandeepan Nath”会返回 Sandeepan Nath。
- 搜索“Sandeepan first”会返回 Sandeepan Nath。
- 搜索“Sandeepan second”不会返回 Sandeepan Nath。
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问题
上述查询返回的结果是正确的(AND 逻辑按预期工作),但是在重负载数据库上查询所花费的时间大约为 25 秒,而正常查询时间为 0.005 - 0.0002 秒,这使得它完全无法使用。
由于尚未对所有可能的字段进行索引,可能会导致一些延迟,但我希望有一个更好的查询作为解决方案,尽可能优化,显示相同的结果
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标签在这个系统中是如何工作的?
- 当导师注册时,会输入标签并根据导师的详细信息(如姓名、姓氏等)创建标签关系。
- 当导师创建包时,再次输入标签并根据包的详细信息(如包名称、描述等)创建标签关系。
- 存储在tutors_tag_relations 中的导师的标签关系和存储在learning_packs_tag_relations 中的包的标签关系。所有单个标签都存储在标签表中。
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桌子
以下大部分表格包含许多其他字段,我在这里省略了。
CREATE TABLE IF NOT EXISTS `users` (
`id_user` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(100) NOT NULL DEFAULT '',
`surname` varchar(155) NOT NULL DEFAULT '',
PRIMARY KEY (`id_user`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ;
CREATE TABLE IF NOT EXISTS `tutor_details` (
`id_tutor` int(10) NOT NULL AUTO_INCREMENT,
`id_user` int(10) NOT NULL DEFAULT '0',
PRIMARY KEY (`id_tutor`),
KEY `Users_FKIndex1` (`id_user`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ;
CREATE TABLE IF NOT EXISTS `orders` (
`id_order` int(10) unsigned NOT NULL AUTO_INCREMENT,
PRIMARY KEY (`id_order`),
KEY `Orders_FKIndex1` (`id_user`),
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ;
ALTER TABLE `orders`
ADD CONSTRAINT `Orders_ibfk_1` FOREIGN KEY (`id_user`) REFERENCES `users`
(`id_user`) ON DELETE NO ACTION ON UPDATE NO ACTION;
CREATE TABLE IF NOT EXISTS `order_details` (
`id_od` int(10) unsigned NOT NULL AUTO_INCREMENT,
`id_order` int(10) unsigned NOT NULL DEFAULT '0',
`id_author` int(10) NOT NULL DEFAULT '0',
PRIMARY KEY (`id_od`),
KEY `Order_Details_FKIndex1` (`id_order`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ;
ALTER TABLE `order_details`
ADD CONSTRAINT `Order_Details_ibfk_1` FOREIGN KEY (`id_order`) REFERENCES `orders`
(`id_order`) ON DELETE NO ACTION ON UPDATE NO ACTION;
CREATE TABLE IF NOT EXISTS `learning_packs` (
`id_lp` int(10) unsigned NOT NULL AUTO_INCREMENT,
`id_author` int(10) unsigned NOT NULL DEFAULT '0',
PRIMARY KEY (`id_lp`),
KEY `Learning_Packs_FKIndex2` (`id_author`),
KEY `id_lp` (`id_lp`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ;
CREATE TABLE IF NOT EXISTS `tags` (
`id_tag` int(10) unsigned NOT NULL AUTO_INCREMENT,
`tag` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id_tag`),
UNIQUE KEY `tag` (`tag`),
KEY `id_tag` (`id_tag`),
KEY `tag_2` (`tag`),
KEY `tag_3` (`tag`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ;
CREATE TABLE IF NOT EXISTS `tutors_tag_relations` (
`id_tag` int(10) unsigned NOT NULL DEFAULT '0',
`id_tutor` int(10) DEFAULT NULL,
KEY `Tutors_Tag_Relations` (`id_tag`),
KEY `id_tutor` (`id_tutor`),
KEY `id_tag` (`id_tag`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
ALTER TABLE `tutors_tag_relations`
ADD CONSTRAINT `Tutors_Tag_Relations_ibfk_1` FOREIGN KEY (`id_tag`) REFERENCES
`tags` (`id_tag`) ON DELETE NO ACTION ON UPDATE NO ACTION;
CREATE TABLE IF NOT EXISTS `learning_packs_tag_relations` (
`id_tag` int(10) unsigned NOT NULL DEFAULT '0',
`id_tutor` int(10) DEFAULT NULL,
`id_lp` int(10) unsigned DEFAULT NULL,
KEY `Learning_Packs_Tag_Relations_FKIndex1` (`id_tag`),
KEY `id_lp` (`id_lp`),
KEY `id_tag` (`id_tag`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
ALTER TABLE `learning_packs_tag_relations`
ADD CONSTRAINT `Learning_Packs_Tag_Relations_ibfk_1` FOREIGN KEY (`id_tag`)
REFERENCES `tags` (`id_tag`) ON DELETE NO ACTION ON UPDATE NO ACTION;
==================================================== ==================================
以下是确切的查询(这也包括课程 - 导师可以创建课程并且搜索词与导师创建的课程相匹配):-
SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) AS key_1_total_matches,
SUM(DISTINCT( t.tag LIKE "%democracy%" )) AS key_2_total_matches,
COUNT(DISTINCT( od.id_od )) AS tutor_popularity,
CASE
WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1
AND wc.wc_type = 0
AND wc.class_date > '2010-06-01 22:00:56'
AND wccp.status = 1
AND ( wccp.country_code = 'IE'
OR wccp.country_code IN ( 'INT' )
) ), 0)
) THEN 1
ELSE 0
END AS 'classes_published',
CASE
WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1
AND lp.published = 1
AND lpcp.status = 1
AND ( lpcp.country_code = 'IE'
OR lpcp.country_code IN ( 'INT' )
) ), 0)
) THEN 1
ELSE 0
END AS 'packs_published',
td . *,
u . *
FROM tutor_details AS td
JOIN users AS u
ON u.id_user = td.id_user
LEFT JOIN learning_packs_tag_relations AS lptagrels
ON td.id_tutor = lptagrels.id_tutor
LEFT JOIN learning_packs AS lp
ON lptagrels.id_lp = lp.id_lp
LEFT JOIN learning_packs_categories AS lpc
ON lpc.id_lp_cat = lp.id_lp_cat
LEFT JOIN learning_packs_categories AS lpcp
ON lpcp.id_lp_cat = lpc.id_parent
LEFT JOIN learning_pack_content AS lpct
ON ( lp.id_lp = lpct.id_lp )
LEFT JOIN webclasses_tag_relations AS wtagrels
ON td.id_tutor = wtagrels.id_tutor
LEFT JOIN webclasses AS wc
ON wtagrels.id_wc = wc.id_wc
LEFT JOIN learning_packs_categories AS wcc
ON wcc.id_lp_cat = wc.id_wp_cat
LEFT JOIN learning_packs_categories AS wccp
ON wccp.id_lp_cat = wcc.id_parent
LEFT JOIN order_details AS od
ON td.id_tutor = od.id_author
LEFT JOIN orders AS o
ON od.id_order = o.id_order
LEFT JOIN tutors_tag_relations AS ttagrels
ON td.id_tutor = ttagrels.id_tutor
JOIN tags AS t
ON ( t.id_tag = ttagrels.id_tag )
OR ( t.id_tag = lptagrels.id_tag )
OR ( t.id_tag = wtagrels.id_tag )
WHERE ( u.country = 'IE'
OR u.country IN ( 'INT' ) )
AND CASE
WHEN ( ( t.id_tag = lptagrels.id_tag )
AND ( lp.id_lp > 0 ) ) THEN lp.id_status = 1
AND lp.published = 1
AND lpcp.status = 1
AND ( lpcp.country_code = 'IE'
OR lpcp.country_code IN (
'INT'
) )
ELSE 1
END
AND CASE
WHEN ( ( t.id_tag = wtagrels.id_tag )
AND ( wc.id_wc > 0 ) ) THEN wc.wc_api_status = 1
AND wc.wc_type = 0
AND
wc.class_date > '2010-06-01 22:00:56'
AND wccp.status = 1
AND ( wccp.country_code = 'IE'
OR wccp.country_code IN (
'INT'
) )
ELSE 1
END
AND CASE
WHEN ( od.id_od > 0 ) THEN od.id_author = td.id_tutor
AND o.order_status = 'paid'
AND CASE
WHEN ( od.id_wc > 0 ) THEN od.can_attend_class = 1
ELSE 1
END
ELSE 1
END
GROUP BY td.id_tutor
HAVING key_1_total_matches = 1
AND key_2_total_matches = 1
ORDER BY tutor_popularity DESC,
u.surname ASC,
u.name ASC
LIMIT 0, 20
请注意 - 提供的数据库结构未显示此查询中的所有字段和表
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解释查询输出:- 请看这个截图 http://www.test.examvillage.com/Explain_query.jpg