我正在为 Mac OS X 编写文本编辑器。我需要在 NSTextView 中显示隐藏字符(例如空格、制表符和特殊字符)。我花了很多时间寻找如何做到这一点,但到目前为止我还没有找到答案。如果有人能指出我正确的方向,我将不胜感激。
titaniumdecoy
问问题
5285 次
6 回答
9
这是一个完整的工作和干净的实现
@interface GILayoutManager : NSLayoutManager
@end
@implementation GILayoutManager
- (void)drawGlyphsForGlyphRange:(NSRange)range atPoint:(NSPoint)point {
NSTextStorage* storage = self.textStorage;
NSString* string = storage.string;
for (NSUInteger glyphIndex = range.location; glyphIndex < range.location + range.length; glyphIndex++) {
NSUInteger characterIndex = [self characterIndexForGlyphAtIndex: glyphIndex];
switch ([string characterAtIndex:characterIndex]) {
case ' ': {
NSFont* font = [storage attribute:NSFontAttributeName atIndex:characterIndex effectiveRange:NULL];
[self replaceGlyphAtIndex:glyphIndex withGlyph:[font glyphWithName:@"periodcentered"]];
break;
}
case '\n': {
NSFont* font = [storage attribute:NSFontAttributeName atIndex:characterIndex effectiveRange:NULL];
[self replaceGlyphAtIndex:glyphIndex withGlyph:[font glyphWithName:@"carriagereturn"]];
break;
}
}
}
[super drawGlyphsForGlyphRange:range atPoint:point];
}
@end
要安装,请使用:
[myTextView.textContainer replaceLayoutManager:[[GILayoutManager alloc] init]];
要查找字体字形名称,您必须转到 CoreGraphics:
CGFontRef font = CGFontCreateWithFontName(CFSTR("Menlo-Regular"));
for (size_t i = 0; i < CGFontGetNumberOfGlyphs(font); ++i) {
printf("%s\n", [CFBridgingRelease(CGFontCopyGlyphNameForGlyph(font, i)) UTF8String]);
}
于 2015-04-16T16:51:01.863 回答
5
看看 NSLayoutManager 类。您的 NSTextView 将有一个与之关联的布局管理器,并且布局管理器负责将字符(空格、制表符等)与字形(在屏幕上绘制的该字符的图像)相关联。
在您的情况下,您可能对该replaceGlyphAtIndex:withGlyph:
方法最感兴趣,它允许您替换单个字形。
于 2008-11-18T21:07:24.350 回答
3
几年前我写了一个文本编辑器——这里有一些毫无意义的代码应该让你(希望)找到正确的方向(顺便说一句,这是一个 NSLayoutManager 子类——是的,我知道它像众所周知的厨房水槽一样泄漏):
- (void)drawGlyphsForGlyphRange:(NSRange)glyphRange atPoint:(NSPoint)containerOrigin
{
if ([[[[MJDocumentController sharedDocumentController] currentDocument] editor] showInvisibles])
{
//init glyphs
unichar crlf = 0x00B6;
NSString *CRLF = [[NSString alloc] initWithCharacters:&crlf length:1];
unichar space = 0x00B7;
NSString *SPACE = [[NSString alloc] initWithCharacters:&space length:1];
unichar tab = 0x2192;
NSString *TAB = [[NSString alloc] initWithCharacters:&tab length:1];
NSString *docContents = [[self textStorage] string];
NSString *glyph;
NSPoint glyphPoint;
NSRect glyphRect;
NSDictionary *attr = [[NSDictionary alloc] initWithObjectsAndKeys:[NSUnarchiver unarchiveObjectWithData:[[NSUserDefaults standardUserDefaults] objectForKey:@"invisiblesColor"]], NSForegroundColorAttributeName, nil];
//loop thru current range, drawing glyphs
int i;
for (i = glyphRange.location; i < NSMaxRange(glyphRange); i++)
{
glyph = @"";
//look for special chars
switch ([docContents characterAtIndex:i])
{
//space
case ' ':
glyph = SPACE;
break;
//tab
case '\t':
glyph = TAB;
break;
//eol
case 0x2028:
case 0x2029:
case '\n':
case '\r':
glyph = CRLF;
break;
//do nothing
default:
glyph = @"";
break;
}
//should we draw?
if ([glyph length])
{
glyphPoint = [self locationForGlyphAtIndex:i];
glyphRect = [self lineFragmentRectForGlyphAtIndex:i effectiveRange:NULL];
glyphPoint.x += glyphRect.origin.x;
glyphPoint.y = glyphRect.origin.y;
[glyph drawAtPoint:glyphPoint withAttributes:attr];
}
}
}
[super drawGlyphsForGlyphRange:glyphRange atPoint:containerOrigin];
}
于 2009-02-23T06:00:54.907 回答
2
我解决了NSGlyphs和NSTextView中对应的unichar之间转换的问题。下面的代码运行良好,并用项目符号替换可见文本的空格:
- (void)drawGlyphsForGlyphRange:(NSRange)range atPoint:(NSPoint)origin
{
NSFont *font = [[CURRENT_TEXT_VIEW typingAttributes]
objectForKey:NSFontAttributeName];
NSGlyph bullet = [font glyphWithName:@"bullet"];
for (int i = range.location; i != range.location + range.length; i++)
{
unsigned charIndex = [self characterIndexForGlyphAtIndex:i];
unichar c =[[[self textStorage] string] characterAtIndex:charIndex];
if (c == ' ')
[self replaceGlyphAtIndex:charIndex withGlyph:bullet];
}
[super drawGlyphsForGlyphRange:range atPoint:origin];
}
于 2008-11-19T06:31:43.087 回答
2
也许 -[NSLayoutManager setShowsControlCharacters:] 和/或 -[NSLayoutManager setShowsInvisibleCharacters:] 会做你想做的事。
于 2009-02-23T03:53:29.253 回答
1
这是 Pol 在 Swift 中的解决方案:
class MyLayoutManager: NSLayoutManager {
override func drawGlyphsForGlyphRange(glyphsToShow: NSRange, atPoint origin: NSPoint) {
if let storage = self.textStorage {
let s = storage.string
let startIndex = s.startIndex
for var glyphIndex = glyphsToShow.location; glyphIndex < glyphsToShow.location + glyphsToShow.length; glyphIndex++ {
let characterIndex = self.characterIndexForGlyphAtIndex(glyphIndex)
let ch = s[startIndex.advancedBy(characterIndex)]
switch ch {
case " ":
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
let g = font.glyphWithName("periodcentered")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)
}
case "\n":
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
// let g = font.glyphWithName("carriagereturn")
let g = font.glyphWithName("paragraph")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)
}
case "\t":
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
let g = font.glyphWithName("arrowdblright")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)
}
default:
break
}
}
}
super.drawGlyphsForGlyphRange(glyphsToShow, atPoint: origin)
}
}
并列出字形名称:
func listFonts() {
let font = CGFontCreateWithFontName("Menlo-Regular")
for var i:UInt16 = 0; i < UInt16(CGFontGetNumberOfGlyphs(font)); i++ {
if let name = CGFontCopyGlyphNameForGlyph(font, i) {
print("name: \(name) at index \(i)")
}
}
}
于 2015-11-24T11:01:14.527 回答