I would like to start a list of promises and execute a callback when all of then are done (without async/await).
问问题
141 次
2 回答
4
我刚刚想通了。只需使用 Promise.all:
function x(timeout) {
return new Promise((resolve, reject) => {
setTimeout(function() {
resolve(timeout + ' done!');
}, timeout);
});
}
(function() {
Promise.all([
x(300),
x(200),
x(100),
]).then(([x300, x200, x100]) => {
console.log(x100);
console.log(x200);
console.log(x300);
});
})();
于 2015-04-30T20:31:27.320 回答
0
是的,Promise.all 是你的朋友。
Promise.all([promise1, promise2]).then(([result1, result2]) => {})
为什么你不使用 async/await 我发现它真的简化了这种模式?
const [result1, result2] = await Promise.all([promise1, promise2])
https://www.dalejefferson.com/blog/async-await-promise-all-array-destructuring/
于 2018-02-06T22:04:41.193 回答