0

过程:

  1. 创建Player类。

  2. 创建播放器List<Player>()

  3. 将玩家添加到列表中。

  4. 写一个json串行文件。

    当我单击writeJson按钮时,我收到错误:

    "Type `'EditPlayers.Player'` cannot be serialized. Consider marking it with the 
    `DataContractAttribute` attribute, and marking all of its members you want serialized 
    with the `DataMemberAttribute` attribute.  If the type is a collection, consider marking 
    it with the `CollectionDataContractAttribute`.See the Microsoft .NET Framework 
    documentation for other supported types."
    

问题:

如何List<Player>()CollectionDataContractAttribute.

class Player
{
    public int MemberId { get; set; }
    public int Gender { get; set; }
    public string LName { get; set; }
    public string FName { get; set; }
    public int Tee { get; set; }
    public int Team { get; set; }
    public int Flight { get; set; }
    public int Ohc { get; set; }
    public decimal HcIx { get; set; }
}

private async void writeJason_Click(object sender, RoutedEventArgs e)
{
    try
    {
        await writeJsonAsync();
    }
    catch
    {

    }
}

private async void readJason_Click(object sender, RoutedEventArgs e)
{
    await deserializerJsonAsync();
}

private List<Player> buildObjectGraph()
{
    var players = new List<Player>();
    players.Add(new Player() {MemberId=1, Gender=0, LName="Player", FName="New", Tee=1, Team=0, Flight=0, Ohc=0, HcIx=0M});
    players.Add(new Player() {MemberId=2, Gender=0, LName="Draw", FName="Blind", Tee=1, Team=0, Flight=0, Ohc=0, HcIx=0M});
    players.Add(new Player() {MemberId=3, Gender=0, LName="Moles", FName="Mike", Tee=1, Team=4, Flight=1, Ohc=2, HcIx=2.0M});
    players.Add(new Player() {MemberId=4, Gender=0, LName="Broemeling", FName="Donald", Tee=1, Team=4, Flight=2, Ohc=10, HcIx=10.0M});
    players.Add(new Player() {MemberId=5, Gender=0, LName="Nelson", FName="David", Tee=1, Team=4, Flight=3, Ohc=11, HcIx=11.7M});
    players.Add(new Player() {MemberId=6, Gender=0, LName="Moles", FName="David", Tee=1, Team=4, Flight=4, Ohc=20, HcIx=20.0M});
    players.Add(new Player() {MemberId=7, Gender=0, LName="Player", FName="A", Tee=1, Team=1, Flight=1, Ohc=0, HcIx=0M});
    players.Add(new Player() {MemberId=8, Gender=0, LName="Player", FName="B", Tee=1, Team=1, Flight=2, Ohc=0, HcIx=0M});
    players.Add(new Player() {MemberId=9, Gender=0, LName="Player", FName="C", Tee=1, Team=1, Flight=3, Ohc=0, HcIx=0M});
    players.Add(new Player() {MemberId=10,Gender=0, LName="Player", FName="D", Tee=1, Team=1, Flight=4, Ohc=0, HcIx=0M});
    return players;
}
private async Task writeJsonAsync()
{
    var allPlayers = buildObjectGraph();
    var serializer = new DataContractJsonSerializer(typeof(List<Player>));
    //using (var stream = await ApplicationData.Current.LocalFolder.OpenStreamForWriteAsync(
    //    JSONFILENAME,
    //    CreationCollisionOption.ReplaceExisting))
    using (var stream = await ApplicationData.Current.LocalFolder.OpenStreamForWriteAsync(
    JSONFILENAME, CreationCollisionOption.ReplaceExisting))
    {
        serializer.WriteObject(stream, allPlayers);
    }
    resultTextBlock.Text = "Write succeeded";
}
4

1 回答 1

0

你不需要用List<Player>()标记CollectionDataContractAttribute。相反,您需要使Player该类可序列化DataContractJsonSerializer,如文档所述:Data Contract Serializer 支持的类型

最简单的解决方案是Player使用Serializable属性进行标记:

[Serializable]
class Player
{
    // Remainder unchanged
}

或者,您可以使用[DataContract][DataMember]属性对其进行注释:

[DataContract]
class Player
{
    [DataMember]
    public int MemberId { get; set; }
    [DataMember]
    public int Gender { get; set; }
    [DataMember]
    public string LName { get; set; }
    [DataMember]
    public string FName { get; set; }
    [DataMember]
    public int Tee { get; set; }
    [DataMember]
    public int Team { get; set; }
    [DataMember]
    public int Flight { get; set; }
    [DataMember]
    public int Ohc { get; set; }
    [DataMember]
    public decimal HcIx { get; set; }
}

无论哪种方式,您List<Player>都可以通过DataContractJsonSerializer.

请注意,数据合同序列化是可选的,因此您必须使用 标记要序列化的每个属性或字段[DataMember]

于 2015-04-29T17:18:59.297 回答