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我错过了什么，还是我发现了 Visual Studio 错误？

除了错误，使用这种类型的继承是好还是坏？

GCC 4.9.0 产生了我的预期结果：

base.getProperty() 1
otherBase.getProperty() 2
derivedA.getProperty() 1
derivedB.getProperty() 2

但是，VS 2015 (CTP 6) 和 VS 2013 (Update 5 CTP) 都产生了我认为不正确的结果：

base.getProperty() 1
otherBase.getProperty() 2
derivedA.getProperty() 1
derivedB.getProperty() 1

将“class derivedClassB：public derivedClassA，otherBaseClass {”更改为“class derivedClassB：public otherBaseClass，derivedClassA {”会产生我预期的结果。我可能会遗漏一些东西，但是尽管继承自的类的顺序会影响初始化顺序，但我认为它不会影响使用哪个模棱两可的函数——尤其是当有一个 using 语句来澄清否则存在的歧义时。

#include <iostream>
using namespace std;

class baseClass {
public:
    virtual int getProperty() {
        return 1;
    }
};

class otherBaseClass : public baseClass {
public:
    virtual int getProperty() {
        return 2;
    }
};

class derivedClassA : public baseClass {
public:
    void someUniqueThing() {
        cout << "someUniqueThing" << endl;
    }
};

class derivedClassB : public derivedClassA, otherBaseClass {
public:
    using otherBaseClass::getProperty;
};

int main() {
    baseClass base;
    cout << "base.getProperty() " << base.getProperty() << endl;
    otherBaseClass otherBase;
    cout << "otherBase.getProperty() " << otherBase.getProperty() << endl;
    derivedClassA derivedA;
    cout << "derivedA.getProperty() " << derivedA.getProperty() << endl;
    derivedClassB derivedB;
    cout << "derivedB.getProperty() " << derivedB.getProperty() << endl;
}
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