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我刚刚写了一个非常简单的类来测试 Delphi XE8 中的 TDictionary<> 类。

当我尝试显示我添加的记录时,它给我带来了访问冲突错误,我不明白为什么?

这是我的课

unit Unit3;

interface

 uses
  Classes, System.SysUtils, System.Types, REST.Types, System.JSON, Data.Bind.Components,
  System.RegularExpressions, System.Variants,
  Generics.Collections, FMX.Dialogs {$IFDEF DEBUG}, CodeSiteLogging{$ENDIF};

type

  TAArray2 = class;

  PTRec=^TRec;

  TRec = class
  public
    Key : Variant;
    isRequired : boolean;
    Value : Variant;
    OldValue : Variant;
    JSON : string;
    Items : TAArray2;
    procedure Add(Key : Variant ; Value: TRec);
  end;

   TAArray2 = class(TDictionary<Variant, TRec>)
   private
     function Get(Index: variant): TRec;
   public
     destructor Destroy; override;
     procedure Add(Key : Variant ; Value: TRec);
     property Items[Cle : Variant]: TRec read Get; default;
   end;

implementation

procedure TRec.Add(Key : Variant ; Value: TRec);
begin
  if not(assigned(items)) then
    self.Items := TAArray2.Create;
  Items.Add( Key, Value);
  showmessage(inttostr(items.Count)); // this show 1 means items is instanciate and contain the proper data
end;

function TAArray2.Get(Index: Variant): TRec;
begin
  Result := inherited items[Index]
end;

end.

然后我正在使用此代码对其进行测试:(带有 1 个 TButton 和 1 个 TMemo 的表单)

procedure TForm1.ShowAssocArray2(AAA : TAArray2 ; Level : integer);
var
  s : string;
  MyRec : TRec;
begin
  for MyRec in AAA.Values Do
  begin
    FillChar(s, Level * 4, ' ');
    memo1.Lines.Add(s + string(MyRec.Key) + ' = ' + string(MyRec.Value));
    if MyRec.Items.Count > 0 then  // ERROR HERE
      ShowAssocArray2(MyRec.items, Level + 1);   // recursive for childrens
  end;
end;

procedure TForm1.Button4Click(Sender: TObject);
var
  MyList : TAArray2;
  MyRec : TRec;
  i : Integer;
begin
  MyList := TAArray2.Create;
  for i := 0 to 9 do
  begin
    MyRec := TRec.Create;
    MyRec.Value := 'Value_' + inttostr(i);
    MyRec.Key := 'No_' + inttostr(i);
    MyList.Add(MyRec.Key, MyRec);
  end;
  // subitem
  MyRec := TRec.Create;
  MyRec.Value := 'test' + inttostr(i);
  MyRec.Key := 'test' + inttostr(i);
  MyList.Items['No_3'].Add('Extra', MyRec);

  memo1.Lines.Add('Nb of Record : ' + inttostr(MyList.Count));

  ShowAssocArray2(MyList, 0);

end;

我尝试了很多方法:MyRec.Items.Count 或 MyRec.Values.Count 或 MyRec.Items.Values.count ......我总是有一个错误,我不明白为什么?

4

2 回答 2

1

这是一个剥离版本,它执行:

program Project20;

{$APPTYPE CONSOLE}

{$R *.res}

uses
  System.SysUtils,Generics.Collections,StrUtils;


type
  TAArray2 = class;

  TRec = class
  public
    Key : Variant;
    Value : Variant;
    Items : TAArray2;
    procedure Add(Key : Variant ; Value: TRec);
  end;

   TAArray2 = class(TDictionary<Variant, TRec>)
   private
     function Get(Index: variant): TRec;
   public
     destructor Destroy; override;
     //procedure Add(Key : Variant ; Value: TRec);
     property Items[Cle : Variant]: TRec read Get; default;
   end;

procedure TRec.Add(Key : Variant ; Value: TRec);
begin
  if not(assigned(items)) then
    self.Items := TAArray2.Create;
  Items.Add( Key, Value);
  WriteLn(inttostr(items.Count)); // this show 1 means items is instanciate and contain the proper data
end;

destructor TAArray2.Destroy;
begin

  inherited;
end;

function TAArray2.Get(Index: Variant): TRec;
begin
  Result := inherited items[Index]
end;

procedure ShowAssocArray2(AAA : TAArray2 ; Level : integer);
var
  s : string;
  MyRec : TRec;
begin
  s := DupeString(' ',Level * 4);
  for MyRec in AAA.Values Do
  begin
    WriteLn(s + string(MyRec.Key) + ' = ' + string(MyRec.Value));
    if Assigned(MyRec.Items) then // <-- Test if Items is assigned
     if MyRec.Items.Count > 0 then 
      ShowAssocArray2(MyRec.items, Level + 1);   // recursive for childrens
  end;
end;

var
  MyList : TAArray2;
  MyRec : TRec;
  i : Integer;
begin
  MyList := TAArray2.Create;
  for i := 0 to 9 do
  begin
    MyRec := TRec.Create;
    MyRec.Value := 'Value_' + inttostr(i);
    MyRec.Key := 'No_' + inttostr(i);
    MyList.Add(MyRec.Key, MyRec);
  end;
  // subitem
  MyRec := TRec.Create;
  MyRec.Value := 'test' + inttostr(i);
  MyRec.Key := 'test' + inttostr(i);
  MyList.Items['No_3'].Add('Extra', MyRec);

  WriteLn('Nb of Record : ' + inttostr(MyList.Count));

  ShowAssocArray2(MyList, 0);
  ReadLn;
end.

调用FillChar()替换为DupeString(),因为之前没有为字符串分配内存FillChar()

还有一个测试Assigned(MyRec.Items)可以解决未分配项目时的情况,这是您的访问冲突的原因

这会执行,但我没有分析结果是否是你想要的。不要忘记确保也没有内存泄漏。

打印输出:

1
Nb of Record : 10
No_4 = Value_4
No_3 = Value_3
    test10 = test10
No_9 = Value_9
No_7 = Value_7
No_8 = Value_8
No_1 = Value_1
No_2 = Value_2
No_5 = Value_5
No_0 = Value_0
No_6 = Value_6
于 2015-04-29T05:08:22.947 回答
0

您永远不会在 TREC 中创建字典,因为您永远不会在创建它的 TREC 上调用 add 函数。

于 2015-04-28T23:31:36.420 回答