2

这是我上一个关于同一代码块的问题的链接，其中包含一个工作切丝示例

好的，我是 C# ASP.NET 开发人员，遵循以下命令：命令是获取给定的数据集，分解 XML 并返回列。我认为在 ASP.NET 端进行粉碎更容易，我们已经可以访问诸如反序列化器等的东西，以及已知类型的整个复合体，但是不，老板说“在服务器上粉碎它，返回一个数据集，将数据集绑定到gridview的列”所以现在，我正在做我被告知的事情。这一切都是为了阻止那些会过来说“不好的要求”的人。

手头的任务：

当前无效的代码：

如果我们修改上一篇文章以在 XML 元素上包含命名空间，我们就会失去上一篇文章所具有的功能......

DECLARE @table1 AS TABLE (
    ProductID    VARCHAR(10)
  , Name         VARCHAR(20)
  , Color        VARCHAR(20)
  , UserEntered  VARCHAR(20)
  , XmlField     XML
)

INSERT INTO @table1 SELECT '12345','ball','red','john','<sizes xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><size xmlns="http://example.com/ns" name="medium"><price>10</price></size><size xmlns="http://example.com/ns" name="large"><price>20</price></size></sizes>'
INSERT INTO @table1 SELECT '12346','ball','blue','adam','<sizes xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><size xmlns="http://example.com/ns" name="medium"><price>12</price></size><size xmlns="http://example.com/ns" name="large"><price>25</price></size></sizes>'
INSERT INTO @table1 SELECT '12347','ring','red','john','<sizes xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><size xmlns="http://example.com/ns" name="medium"><price>5</price></size><size xmlns="http://example.com/ns" name="large"><price>8</price></size></sizes>'
INSERT INTO @table1 SELECT '12348','ring','blue','adam','<sizes xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><size xmlns="http://example.com/ns" name="medium"><price>8</price></size><size xmlns="http://example.com/ns" name="large"><price>10</price></size></sizes>'
INSERT INTO @table1 SELECT '23456','auto','black','ann','<auto xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><type xmlns="http://example.com/ns">car</type><wheels xmlns="http://example.com/ns">4</wheels><doors xmlns="http://example.com/ns">4</doors><cylinders xmlns="http://example.com/ns">3</cylinders></auto>'
INSERT INTO @table1 SELECT '23457','auto','black','ann','<auto xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><type xmlns="http://example.com/ns">truck</type><wheels xmlns="http://example.com/ns">4</wheels><doors xmlns="http://example.com/ns">2</doors><cylinders xmlns="http://example.com/ns">8</cylinders></auto><auto xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"><type xmlns="http://example.com/ns">car</type><wheels xmlns="http://example.com/ns">4</wheels><doors xmlns="http://example.com/ns">4</doors><cylinders xmlns="http://example.com/ns">6</cylinders></auto>'

DECLARE @x XML
-- I think I'm supposed to use WITH XMLNAMESPACES(...) here but I don't know how
SELECT @x = (
    SELECT 
        ProductID
      , Name
      , Color
      , UserEntered
      , XmlField.query('
            for $vehicle in //auto
            return <auto 
                type = "{$vehicle/type}"
                wheels = "{$vehicle/wheels}"
                doors = "{$vehicle/doors}"
                cylinders = "{$vehicle/cylinders}"
            />')
    FROM @table1 table1
    WHERE Name = 'auto'
    FOR XML AUTO
)

SELECT @x

SELECT 
    ProductID    = T.Item.value('../@ProductID', 'varchar(10)')
  , Name         = T.Item.value('../@Name', 'varchar(20)')
  , Color        = T.Item.value('../@Color', 'varchar(20)')
  , UserEntered  = T.Item.value('../@UserEntered', 'varchar(20)')
  , VType        = T.Item.value('@type' , 'varchar(10)')
  , Wheels       = T.Item.value('@wheels', 'varchar(2)')
  , Doors        = T.Item.value('@doors', 'varchar(2)')
  , Cylinders    = T.Item.value('@cylinders', 'varchar(2)')
FROM   @x.nodes('//table1/auto') AS T(Item)

如果我之前的帖子显示有更好的方法可以做到这一点，那么我真的需要修改这个问题，但是如果这种编码风格很好，我可能会照原样继续。

4

1 回答 1

4 
DECLARE @x XML;
with xmlnamespaces ('http://www.w3.org/2001/XMLSchema-instance' as xsi
    , 'http://www.w3.org/2001/XMLSchema' as xsd
    , 'http://example.com/ns' as ns) 
SELECT @x = (
    SELECT 
        ProductID
      , Name
      , Color
      , UserEntered
      , XmlField.query('
            for $vehicle in //auto
            return <auto 
                type = "{$vehicle/ns:type}"
                wheels = "{$vehicle/ns:wheels}"
                doors = "{$vehicle/ns:doors}"
                cylinders = "{$vehicle/ns:cylinders}"
            />')
    FROM @table1 table1
    WHERE Name = 'auto'
    FOR XML AUTO
)
于 2010-06-07T20:57:34.857 回答